AP Board 7th Class Maths Solutions Chapter 6 Data Handling InText Questions

SCERT AP 7th Class Maths Solutions Pdf Chapter 6 Data Handling InText Questions and Answers.

AP State Syllabus 7th Class Maths Solutions 6th Lesson Data Handling InText Questions

[Page No. 108]

Where does the Arithmetic Mean lie ?
The marks obtained by Sarala, Bindu, Geeta and Rekha in Telugu, Hindi and English are given below.

Answer:
Now, let us calculate the average marks obtained by the students in each subject.

Answer:

(i) What do you observe from the above table ?
Answer:
Mean always lie between the maximum and minimum values/observations of the data.

(ii) Does the mean lies between maximum and minimum values in each case ?
Answer:
Yes, Its always true.
i.e., Mean always lies between the maximum and minimum values of the data.

Check Your Progress [Page No: 109]

Question 1.
Find the Arithmetic Mean of first three multiples of 5 ?
Answer:
Given, first three multiples of 5 are: 5, 10, 15.
Sum of observations = 5 + 10 + 15 = 30
Number of observations = 3
Arithmetic mean =\(\frac{\text { Sum of observations }}{\text { Number of observations }}\) = \(\frac{30}{3}\) = 10
∴ Arithmetic mean of first three multiples of 5 is 10.

Let’s Explore [Page No. 109]

Collect the information about the weights of any ten students of your class in kilograms arid answer the following:

Answer:

Name of the student	Weight in kilograms
Aditya	38
Kishore	39
Balu	40
Sreeja	36
Sreekari	35
Kairavi	3.7
Swathi	36
Kirshna	41
Ram	39
Prasad	39

Question 1.
What are the greatest and smallest weights ?
Answer:
Krishna = 41 kg – Greatest weight
Sreekari = 35 kg – Smallest weight

Question 2.
Find Arithmetic mean of collected data.
Answer:
Given observations: 38, 39, 40, 36, 35, 37, 36, 41, 39, 39.
Sum of observations = 38 + 39 + 40 + 36 + 35 + 37 + 36 + 41 + 39 + 39 = 380
Number of observations = 10
Arithmetic Mean = \(\frac{\text { Sum of observations }}{\text { Number of observations }}\) = \(\frac{380}{10}\) = 38 kg.
Number of observations 10
∴ Arithmetic mean weight of 10 students of our class is 38 kg.

Question 3.
Verify whether Arithmetic Mean lies between greatest and smallest observations or not.
Answer:
Yes, Arithmetic mean 38 kg lies between greatest weight 41 kg and smallest weight 35 kg.

Check Your Progress [Page No. 110]

Question 1.
What is the range of first ten whole numbers?
Answer:
First ten wh4’e numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
Maximum value = 9
Minimum value = 0
Range = Maximum Value – Minimum Value = 9 – 0 = 9
∴ Range = 9

Check Your Progress [Page No. 111]

Find the mode of 10, 9, 12, 10, 8, 7, 6, 10, 9, 7, 8, 5 and 2.
Answer:
Given data : 10, 9, 12, 10, 8, 7, 6, 10, 9, 7, 8, 5 and 2.
By arranging the numbers with same values together.
2, 5, 6, 7, 7, 8, 8, 9, 9, 10, 10, 10, 12
As ’10’ occurs more frequently than other observations.
∴ Mode = 10

Let’s Explore [Page No. 111]

Take a dice, roll it 20 times and record the numbers you got on its top face. Find the ‘Mode’ of resulting numbers.
Answer:
A dice rolled 20 times and the numbers are
2, 4, 5, 3, 1, 6, 5, 4, 2, 1, 3, 5, 4, 2, 6, 2, 2, 5, 1, 3.
By arranging the numbers with same values together
1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 6, 6.
As 2 occurs more frequently than other observations.
Mode = 2.

Let’s Think [Page No: 111]

The following data shows that the number of hours spent by students for study. Find the mode:

Answer:
In the given data more number of students spend 1 hour for study.
So, mode of the data = 4.

Check Your Progress [Page No: 114]

What is the median of first 7 prime numbers ?
Answer:
First 7 prime numbers are 2, 3, 5, 7, 11,13, 17.
Arrange the given observations in ascending order

In seven observations the 4th observation 7 is the middle most value.
∴ Median = 7.

Let’s Explore [Page Mo. 114]

Question 1.
Collect 10th class pass percentage for last six years of your school (or) your near by school. Find median of the data.
Answer:
10th Class pass percentage for last six years of our school are: 100%, 98%, 93%, 95%, 96%, 97%.
Arrange the given observations in ascending order.

In six observations the 3rd and 4th observations are 96% and 97%.
Here, we have two middle most values 96% and 97%.
Median = Average of two middle most values
= \(\frac{96+97}{2}\) = 96.5%
∴ Median of the data = 96.5%

Project Work [Page No: 114]

Visit any vegetable market along with your parent. Collect the information about the costs of different vegetables. By using this data fill the following table.

Answer:

[Page No. 115]

Prasanna wanted to buy a mobile phone. He selected two mobile phones of different companies having same features. Now he would like to know which mobile phone has good performance. He collected the information of star rating from different magazines and news papers.

Question 1.
What information is given in the table ?
Answer:
The table is showing information about the mobile phones.

Question 2.
Is the above information being useful to Prasanna ?
Answer:
Yes.

Question 3.
Which mobile phone you will suggest to Prasanna ?
Answer:
Mobile A. (21 + \(\frac{1}{2}\) + \(\frac{1}{2}\) rating)

Check Your Progress [Page No. 116]

Observe the adjacent bar graph and answer the following.

Question 1.
Which fruit most of the people like ?
Answer:
Most of the people liked Apple.

Question 2.
How many people likes banana?
Answer:
10.

Observe the following graph. [Page No. 116]

Observe the above double bar graph and answer the following:

Question 1.
In which year the sales of both mobile phone companies are equal ?
Answer:
2018.

Question 2.
In 2017, which mobile phone company has more sales ?
Answer:
Mobile phone – A.

Examples

Question 1.
Mid Day Meal (MDM) taken by the students in six days are 132, 164, 145, 182, 163 and 114, Find Arithmetic Mean of students who took MDM per day.
Answer:
Given, number of students who took MDM 132, 164, 145, 182, 163, 114.
Arithmetic Mean = \(\frac{\text { Sum of observations }}{\text { Number of observations }}\)
= \(\frac{132+164+145+182+163+114}{6}\)
= \(\frac{900}{6}\)
= 150

Question 2.
Ages of students (in years) are 8, 5, 6, 6, 5, 7, 5, 6, 5, 4 7, 6, 7, 6, 5 8 and 6 find the mode of given data.
Answer:
Given, ages of students are 8, 5, 6, 6, 5, 7, 5, 6, 5, 4, 7, 6, 7, 6, 5, 8, 6.
By arranging the numbers with same values together
4, 5, 5, 5, 5,5,6, 6,6,6, 6, 6,7,7, 7, 8, 8.
As 6’ occurs more frequently than other observations.
∴ Mode = 6

Question 3.
Find the mode of the data of Grades A, B, E, A, C, E, B, C, D, A, D, C, F, A and C.
Answer:
Given, A, B, E, A, C, E, B, C, D, A, D, C, F, A, C.
By arranging the letters of same type together
A, A, A, A, B, B, C, C, C, C, D, D, E, E, F
As ‘A’ and ‘C’ occurs most frequently in the data.
∴ Mode = A and C

Question 4.
Find the median of data 32, 43, 25, 67, 46, 71 and 182.
Answer:
Given 32, 43, 25, 67, 46, 71, 182
Arrange the given observations in ascending order.

In ‘7’ observations the 4th observation is the middle most value.
∴ Median = 46.

Question 5.
The monthly incomes of 8 members are ₹8000, ₹9000, f8200, ₹7900, ₹8500, ₹8600, ₹7700 and ₹60000. Find the median income.
Answer:
Given that, the monthly incomes of 8 members are:
₹8000, ₹9000, ₹8200, ₹7900, ₹8500, ₹8600, ₹7700, ₹60000
Arrange the given observations in ascending order.

Here, we have two middle most values 8200 and 8500.
In this case, Median = Average of two middle most values
8200 + 8500 16700
= \(\frac{8200+8500}{2}\) = \(\frac{16700}{2}\) = ₹8,350

Question 6.
The number of CFL bulbs and LED bulbs by a seller every month from March to August are given below. Draw by vertical double bar graph.

Month	CFL Bulbs	LED Bulbs
March	70	75
April	35	30
May	65	75
June	90	100
July	22	35
August	50	50

Answer:
Steps in drawing a Double bar graph:

1. Draw X-axis (horizontal line) and Y – axis (vertical line) on the graph paper and mark their intersection point as ‘O’.
2. Take ‘months’ on X – axis.
3. Take number of CFL and LED bulbs on Y ~ axis.
4. Take an appropriate scale on Y-axis so that number of both the bulbs can be shown easily. Here the maximum value to be plotted on Y – axis as 100, so let us take 1 cm =10 bulbs on Y – axis.
5. Find the length of each bar by dividing the value by 10 (as scale is 1 cm = 10 bulbs).

Eg: Length of bar represents 70 CFL bulbs = \(\frac{70}{10}\) = 7 cm
Length of bar represents 75 LED bulbs = \(\frac{75}{10}\) = 7.5 cm

Question 6.
Draw the bars of uniform width representing ‘CFL bulb’ and ‘LED bulb’ side by side of every month.

Observe the adjacent figure:

Question 1.
Largest portion of the circle is shaded by which colour ?
Answer:
Red.

Question 2.
Are the portions of circle shaded by blue and pink are in same size ?
Answer:
No.

Question 3.
Smallest portion of the circle is shaded by which colour ?
Answer:
Yellow.

Question 2.
Observe the below picture which shows various expenses of Manasa’s family:

(i) For which item highest amount spent?
Answer:
Food.

(ii) For which items same amount spent?
Answer:
Charity and Education.

(iii) For which item least amount spent?
Answer:
Others.

Question 7.
In a school, there are 100 students in class VII and every student is a member of any one of the club. The following table shows the number of students in various clubs, then Construct the pie chart to following data:

Club	Number of members
Mathematics	50
Science	30
Social Studies	40
English	40
Arts	20

Answer:
The angle of each sector will depend on the ratio between the number of students in club and total number of students.
Angle of sector = \(\frac{\text { Value of the item }}{\text { Sum of the values of all items }}\) × 360°

Steps of construction:

1. Draw a circle with any convenient radius and mark it’s centre as ‘O’.
2. Mark a point A, somewhere on the circumference and join OA.
3. Construct ∠AOB = 100° to represent angle of the sector for Maths club.
4. Construct ∠BOC = 60° to represent angle of the sector for Science club.
5. Construct ∠COD = 80° to represent angle of the sector for Social Studies club.
6. Construct ∠DOE = 80° to represent angle of the sector for English club.
7. Now ∠EOA = 40° to represent angle of the sector for Arts club.

Practice Questions [Page No: 124]

In the following alphabetical series, a term (next term) is missing. Choose the missing term from the options.

Question 1.
B, F, J, N, R,’V, …..
(a) Z
(b) W
(c) X
(d) Y
Answer:
(a) Z

Explaination:

So, answer is Z.

Question 2.
A, C, E, G, I, K, …..
(a) P
(b) O
(c) N
(d) M
Answer:
(d) M

Explaination:

So, answer is M.

Question 3.
M, O, R, T, …….
(a) W
(b) U
(c) V
(d) Q
Answer:
(a) W

Explaination:

So, answer is W.

Question 4.
U, S, P, L, …….
(a) F
(b) G
(c) H
(d) I
Answer:
(b) G

Explaination:

So, answer is G.

Question 5.
ZA, YB, XC, WD,
(a) UE
(b) EV
(c) VE
(d) SH
Answer:
(c) VE

Explaination:

So, answer is VE.

Question 6.
AM, BO, CQ, DS, EU, …………
(a) WF
(b) FU
(c) GV
(d) FW
Answer:
(d) FW

Explaination:

In the series next word is FW.

Question 7.
ZY, XV, UR, QM, …..
(a) LG
(b) LI
(c) LH
(d) KJ
Answer:
(a) LG

Explaination:

So, in the series next word is LG.

Question 8.
AC, DF, GI, JL, …..
(a) NO
(b) MO
(c) MN
(d) NP
Answer:
(b) MO

Explaination:

So, in the series next word is MO.

Question 9.
DN, EM, FL, GK, HJ, …..
(a) IK
(b) GI
(c) IJ
(d) II
Answer:
(d) II

Explaination:

So, in the series next word is II.

Question 10.
CBA, STU, FED, VWX,
(a) IHG
(b) GHI
(c) IJK
(d) YZA
Answer:
(a) IHG

Explaination:

So, in the series next word is IHG.

Question 11.
AZC, DYF, GXI, JWL
(a) OVM
(b) UNV
(c) MVO
(d) MNO
Answer:
(c) MVO

Explaination:

So, in the series next word is MVO.

Question 12.
ABK, CDL, EFM, GHN,
(a) JIO
(b) IJO
(c) MNO
(d) ONM
Answer:
(b) IJO

Explaination:

So, in the series next word is IJO.

Question 13.
A2C, D5F, G8I, J11L, …..
(a) Ml40
(b) Ml20
(c) N15P
(d) N12P
Answer:
(a) Ml40

Explaination:

So, in the series next word is M140.

Question 14.
A, CD, HIJ, PQRS, …………..
(a) ZABCD
(b) ZYXW
(c) ABCDE
(d) RSTUV
Answer:
(c) ABCDE

Explaination:

So, in the series next word is ABCDE.

Question 15.
A, BC, DEF, GHIJ,
(a) KLMNP
(b) LMNOP
(c) KLMNO
(d) JKLMN
Answer:
(c) KLMNO

Explaination:
A BC DEF GHIJ KLMNO
So, in the series next word is KLMNO.