SCERT AP 7th Class Maths Solutions Pdf Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.2 Textbook Exercise Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Exercise 2.2

Question 1.

Find the product of the following.

(i) 23.4 × 6

Answer:

= \(\frac{234}{10} \times \frac{6}{1}\)

= \(\frac{1404}{10}\)

∴ 23.4 × 6 = 140.4

(ii) 681.25 × 9

Answer:

681.25 × 9

= \(\frac{68125}{100} \times \frac{9}{1}\)

= \(\frac{68125 \times 9}{100}\)

= \(\frac{613125}{100}\)

∴ 681.25 × 9

= 6131.25

(iii) 53.29 × 14

Answer:

53.29 × 14

= \(\frac{5329}{100} \times \frac{14}{1}\)

= \(\frac{74606}{100}\)

∴ 53.29 × 14

= 746.06

(iv) 8 × 2.52

Answer:

8 × 2.52

= 8 × \(\frac{252}{100}\)

= \(\frac{8 \times 252}{100}\)

= \(\frac{2016}{100}\)

∴ 8 × 2.52 = 20.16

(v) 25 × 2.013

Answer:

25 × 2.013

= 25 × \(\frac{2013}{1000}\)

= \(\frac{25 \times 2013}{1000}\)

= \(\frac{50325}{1000}\)

∴ 25 × 2.013 = 50.325

Question 2.

Fill the blanks in the table.

Answer:

Multiplications | Product |

36.21 × 10 | 362.1 |

23.104 × 100 | 2310.4 |

6.24 × 1000 |
6240.0 |

0.02105 × 1000 |
21.05 |

9.234 × 100 | 923.4 |

1.3004 × 1000 |
1300.4 |

5.9001 × 10 |
59.001 |

Question 3.

Find the product.

(i) 5.1 × 8.1

Answer:

= \(\frac{51}{10} \times \frac{81}{10}\)

= \(\frac{51 \times 81}{10 \times 10}\)

= \(\frac{4131}{100}\)

∴ 5.1 × 8.1 = 41.31

(ii) 63.205 × 0.27

Answer:

63.205 × 0.27

= \(\frac{63205}{1000} \times \frac{27}{100}\)

= \(\frac{63205 \times 27}{1000 \times 100}\)

= \(\frac{1706535}{100000}\)

∴ 63.205 × 0.27 = 17.06535

(iii) 1.321 × 0.9

Answer:

1.321 × 0.9

= \(\frac{1321}{1000} \times \frac{9}{10}\)

= \(\frac{1321 \times 9}{1000 \times 10}\)

= \(\frac{11889}{10000}\)

∴ 1.321 × 0.9 = 1.1889

(iv) 6.51 × 0.99

Answer:

6.51 × 0.99

= \(\frac{651}{100} \times \frac{99}{100}\)

= \(\frac{651 \times 99}{100 \times 100}\)

= \(\frac{64449}{10000}\)

∴ 6.51 × 0.99 = 6.4449

(v) 837.6 × 0.006

Answer:

837.6 × 0.006

= \(\frac{8376}{10} \times \frac{6}{1000}\)

= \(\frac{8376 \times 6}{10 \times 1000}\)

= \(\frac{50256}{10000}\)

∴ 837.6 × 0.006 = 5.0256

Question 4.

Rithesh reads a book for 2.5 hours everyday. If he reads the entire book in a week, then how many hours all together are required for him to read the book ?

Answer:

Given, time taken to read a book per day = 2.5 hours.

Time taken to read entire book in a week (one week = 7 days)

= 2.5 × 7 days

= \(\frac{25}{10}\) × 7

= \(\frac{175}{10}\)

∴ Time taken to read entire book = 17.5 hours.

Question 5.

Find the area of the rectangle whose length and breadth are 5.3 cm, 2.7 cm respectively.

Answer:

Given length of the rectangle l = 5.3 cm

Breadth of the rectangle b = 2.7 cm

Area of the rectangle = l × b

= 5.3 × 2.7

= \(\frac{53}{10} \times \frac{27}{10}\)

= \(\frac{53 \times 27}{10 \times 10}\)

∴ Area of the rectangle = \(\frac{1431}{100}\)

= 14.31 sq.cm

Question 6.

If the cost of each cement bag is ₹ 326.50, then find the cost of 24 bags of cement.

Answer:

Given, cost of each cement bag

= ₹ 326.50

Cost of 24 cement bags

= 326.50 × 24

= \(\frac{32650}{100}\) × 24

= \(\frac{32650 \times 24}{100}\)

= \(\frac{783600}{100}\)

∴ Cost of 24 cement bags = ₹ 7,836.

Question 7.

Dharmika purchased chudidhar material of 1.40 m at the rate of 7152.5 pet irtetre. Find the amount to be paid.

Answer:

Given cost of one meter chudidhar material = 7152.50

Cost of 1.40 meter chudidhar material = 152.50 × 1.40

= \(\frac{15250}{100} \times \frac{140}{100}\)

= \(\frac{15250 \times 140}{100 \times 100}\)

= \(\frac{2135000}{10000}\)

∴ Cost of 1.40 meter chudidhar material = ₹ 213.50

Question 8.

If a picture chart costs 74.25. Amrutha wants to buy 16 charts to make an album. How much money does she has to pay ?

Answer:

Given, cost of one picture chart = ₹ 4.25

Cost of 16 charts = 4.25 × 16

= \(\frac{425}{100}\) × 16

= \(\frac{425 \times 16}{100}\)

∴ Cost of 16 charts to make album = \(\frac{6800}{100}\) = ₹ 68