AP State Syllabus AP Board 7th Class Maths Solutions Chapter 13 Area and Perimeter Ex 1 Textbook Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 12th Lesson Area and Perimeter Exercise 1

Question 1.

Solution:

Question 2.

The measurements of some squares are given in the table below. However, they are incomplete. Find the missing information.

Solution:

i) Perimeter = 4a = 4(15) = 60cm

ii) Perimeter = 4a = 88

a = \(\frac{88}{4}\)= 22

Side = 22cm

Area = a^{2} = (22)^{2} = 484 cm^{2}

Question 3.

The measurements of some rectangles are given in the table below. However, they are incomplete. Find the missing information.

Solution:

Given:

i) Length = 20 cm

breadth = 14cm

Area = l x b = 20 x 14 =280 cm^{2}

Perimeter = 2(l + b) = 2(20 + 14)

= 2(34) = 68cm

ii) Given breadth = 12cm, perimeter = 60cm

Perimeter 2(l + b) 60 cm

= 2(l + 12) =60cm

2l + 24 =60cm

2l = 60 – 24 = 36

2l = \(\frac{36}{2}\) = 18cm

Area = l x b = 18 x 12 = 216cm^{2}

iii) Given length = 15cm, Area = 150 cm

Area = l x b = 15 x b = 150

⇒ b = \(\frac{150}{15}\) = 10cm

Perimeter = 2(l + b) = 2(15 + 10)

= 2(25) =50cm