SCERT AP 7th Class Maths Solutions Pdf Chapter 1 Integers Ex 1.4 Textbook Exercise Questions and Answers.

AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Exercise 1.4

Question 1.
Simplify the following.
(i) 6 × 9 – 6 ÷ 3
Answer:
6 × 9 – 6 ÷ 3 (Division)
= 6 × 9 – 2 (Multiplication)
= 54 – 2 (Subtraction)
= 52

AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4

(ii) 12 ÷ 4 – 8 + 5
Answer:
12 ÷ 4 – 4 – 8 + 5 (Division)
= 3 – 8 + 5
= 3 + 5 – 8 (Addition)
= 8 – 8 (Subtraction)
= 0

(iii) 80 – 56 ÷ 8 × 9
Answer:
80 – 56 ÷ 8 × 9 (Division)
= 80 – 7 × 9 (Multiplication)
= 80 – 63 (Subtraction)
= 17

(iv) 15 ÷ 5 + 17-30
Answer:
15 ÷ 5 + 17 – 30 (Division)
= 3 + 17 – 30 (Addition)
= 20 – 30 (Subtraction)
= – 10

(v) 8 + 8 – 8 × 8 ÷ 8
Answer:
8 + 8 – 8 × 8 ÷ 8 (Division)
= 8 + 8 – 8 × 1 (Multiplication)
= 8 + 8 – 8 (Addition)
= 16 – 8 (Subtraction)
= 8

Question 2.
Simplify the following.
(i) 8 × 3 – \(\overline{13-7}\)
Answer:
8 × 3 – \(\overline{13-7}\) (Vinculum)
= 8 × 3 – 6 (Multiplication)
= 24 – 6 (Subtraction)
= 18

AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4

(ii) {12 – \(\overline{14-8}\) + 7} – 15
Answer:
{12 – \(\overline{14-8}\) + 7} – 15 (Vinculum)
= {12 – 6 + 7} – 15
= {12 + 7 – 6} – 15 (Curly bracket)
= {19 – 6} – 15
= 13 – 15 (Subtraction)
= – 2

(iii) 16 – (4 + 18 ÷ 6 – \(\overline{7-5}\)) × 5
Answer:
16 – (4 + 18 ÷ 6 – \(\overline{7-5}\)) × 5 (Vinculum)
= 16 – (4 + 18 + 6 – 2) × 5 (Division)
= 16 -(4 + 3 – 2) × 5 (Simple bracket)
= 16 – (7 – 2) × 5
= 16 – 5 × 5 (Multiplication)
= 16 – 25 (Subtraction)
= – 9

(iv) {6 of 145 ÷ (3 + 2)} ÷ 2 – 4 of 20
Answer:
{6 of 145 ÷ (3 + 2)} ÷ 2 -4 of 20 (Simple Bracket)
= {6 of 145 ÷ 5} ÷ 2 – 4 of 20 (Of)
= {870 ÷ 5} ÷ 2 – 80 (Curly bracket, Division)
= 174 ÷ 2 – 80 (Division)
= 87 – 80 (Subtraction)
= 7

AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4

(v) 25 + [14 – 18 + {12 of 5 – (- 4 + 14)}]
Answer:
Given
25 + [14 – 18 + {12 of 5 – (- 4 + 14)}]
Applying BODMAS Rule
= 25 + [14 – 18 + {12 of 5 – (10)}]
[Removing inner most in bracket]
= 25 + [14 – 18 + {12 × 5 – 10}] [Replacing of]
= 25 + [14- 18 + {60 – 10}]
= 25 + [- 4 + 50]
= 25 – 4 + 50
= 75 – 4 = 71

Question 3.
Identify the true statements.
(i) 48 ÷ 6 – 4 = 24
Answer:
48 ÷ 6 – 4 = 24 (Division)
8 – 4 = 24 (Subtraction)
4 ≠ 24
It is a false statement.

(ii) – 18 + 12 + 3 = – 14
Answer:
– 18 + 12 ÷ 3 = – 14 (Division)
– 18 + 4 = – 14 (Subtraction)
– 14 = – 14
It is a true statement.

(iii) – 11 + 3 × 7 = – 56
Answer:
– 11 + 3 × 7 = – 56 (Multiplication)
– 11 + 21 = – 56 (Subtraction)
10 ≠ – 56
It is a false statement.

AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4

(iv) 2020 ÷ 20 – 100 = 1
Answer:
2020 ÷ 20 – 100 = 1 (Division)
101 – 100 = 1 (Subtraction)
1 = 1
It is a true statement.

Question 4.
Fill the blanks with +, -, ×, ÷ to make the statement as true.
(i) 9 __ 3 __ 6 = – 3
Answer:
9 ÷ 3 – 6 = – 3 (Division)
3 – 6 = – 3 (Subtraction)
– 3 = – 3

(ii) – 6 __ 12 __ 6 = – 4
Answer:
– 6 + 12 ÷ 6 = – 4 (Division)
– 6 + 2 = – 4 (Subtraction)
– 4 = – 4

AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4

(iii) – 15 __ 3 __ 6 = – 30
Answer:
– 15 ÷ 3 × 6 = – 30 (Division)
– 5 × 6 = – 30 (Multiplication)
– 30 = – 30