AP State Syllabus AP Board 6th Class Maths Solutions Chapter 2 Whole Numbers Ex 2.2 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 2nd Lesson Whole Numbers Exercise 2.2

Question 1.

Find the sum by suitable rearrangement.

i) 238 + 695 + 162

ii) 154 + 197 + 46 + 203

Answer:

i) 238 + 695 + 162 = 238 + 162 + 695 (Commutative property)

= (238 + 162) + 695 (Associative property)

= 400 + 695

= 1095

ii) 154 + 197 + 46 + 203 = 154 + 46 + 197 + 203 (Commutative property)

= (154 + 46) + (197 + 203) (Associative property)

= 200 + 400

= 600

Question 2.

Find the product by suitable rearrangement.

i) 25 × 1963 × 4

ii) 20 × 255 × 50 × 6

Answer:

i) 25 × 1963 × 4 = 25 × (1963 × 4)

= 25 × (4 × 1963) (Commutative property)

= (25 × 4) × 1963 (Associative property)

= 100 × 1963 = 196300

ii) 20 × 255 × 50 × 6 = 20 × 50 × 255 × 6 (Commutative property)

= (20 × 50) × (255 × 6) (Associative property)

= 1000 × 1530

= 15,30,000

Question 3.

Find the product using suitable properties.

1)205 × 1989 ii) 1991 × 1005

Answer:

i) 205 × 1989 = (200 + 5) × 1989

(Distributive property of multiplication over addition)

= (200 × 1989) + (5 × 1989)

= 397800 + 9945

= 407745

ii) 1991 × 1005

= 1991 × (1000 + 5)

Distributive property of multiplication over addition.

= (1991 × 1000)+ (1991 × 5)

= 1991000 + 9955

= 2000955

Question 4.

A milk vendor supplies 56 liters of milk in the morning and 44 liters of milk in the evening to a hostel. If the milk costs Rs. 50 per liter, how much money he gets per day?

Answer:

Capacity of milk supplied in the morning = 56 l

Capacity of milk supplied in the evening = 44 l

Total capacity of milk supplied in one day = (56 + 44)l

Cost of one liter milk = Rs. 50

Cost of (56 + 44) liters milk =(56 + 44) × 50

= 100 × 50

= Rs. 5000

∴ Money got by vendor per day = Rs. 5000