AP State Syllabus AP Board 6th Class Maths Solutions Chapter 2 Whole Numbers Ex 2.2 Textbook Questions and Answers.
AP State Syllabus 6th Class Maths Solutions 2nd Lesson Whole Numbers Exercise 2.2
Question 1.
Find the sum by suitable rearrangement.
i) 238 + 695 + 162
ii) 154 + 197 + 46 + 203
Answer:
i) 238 + 695 + 162 = 238 + 162 + 695 (Commutative property)
= (238 + 162) + 695 (Associative property)
= 400 + 695
= 1095
ii) 154 + 197 + 46 + 203 = 154 + 46 + 197 + 203 (Commutative property)
= (154 + 46) + (197 + 203) (Associative property)
= 200 + 400
= 600
Question 2.
Find the product by suitable rearrangement.
i) 25 × 1963 × 4
ii) 20 × 255 × 50 × 6
Answer:
i) 25 × 1963 × 4 = 25 × (1963 × 4)
= 25 × (4 × 1963) (Commutative property)
= (25 × 4) × 1963 (Associative property)
= 100 × 1963 = 196300
ii) 20 × 255 × 50 × 6 = 20 × 50 × 255 × 6 (Commutative property)
= (20 × 50) × (255 × 6) (Associative property)
= 1000 × 1530
= 15,30,000
Question 3.
Find the product using suitable properties.
1)205 × 1989 ii) 1991 × 1005
Answer:
i) 205 × 1989 = (200 + 5) × 1989
(Distributive property of multiplication over addition)
= (200 × 1989) + (5 × 1989)
= 397800 + 9945
= 407745
ii) 1991 × 1005
= 1991 × (1000 + 5)
Distributive property of multiplication over addition.
= (1991 × 1000)+ (1991 × 5)
= 1991000 + 9955
= 2000955
Question 4.
A milk vendor supplies 56 liters of milk in the morning and 44 liters of milk in the evening to a hostel. If the milk costs Rs. 50 per liter, how much money he gets per day?
Answer:
Capacity of milk supplied in the morning = 56 l
Capacity of milk supplied in the evening = 44 l
Total capacity of milk supplied in one day = (56 + 44)l
Cost of one liter milk = Rs. 50
Cost of (56 + 44) liters milk =(56 + 44) × 50
= 100 × 50
= Rs. 5000
∴ Money got by vendor per day = Rs. 5000