SCERT AP 7th Class Maths Solutions Pdf Chapter 6 Data Handling Ex 6.1 Textbook Exercise Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 6th Lesson Data Handling Ex 6.1

Question 1.
Find Arithmetic Mean of the following.
(i) 4, 5, 11, 8
Given data: 4,5, 11, 8.
Sum of observations = 4 + 5 + 11 + 8 = 28
Number of observations = 4
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$ = $$\frac{28}{4}$$ = 7.

(ii) 10, 15, 21, 12, 17
Given data: 10, 15, 21, 12, 17
Sum of observations 10 + 15 + 21 + 12 + 17 = 75
Number of observations = 5
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$ = $$\frac{75}{5}$$ = 15

(iii) $$\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \frac{3}{2}, \frac{5}{4}$$
Given data: $$\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \frac{3}{2}, \frac{5}{4}$$
Sum of observations = $$\frac{1}{4}+\frac{1}{2}+\frac{3}{4}+\frac{3}{2}+\frac{5}{4}$$ = $$\frac{1+2+3+6+5}{4}$$ = $$\frac{17}{4}$$
Number of observations = 5
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$
= $$\frac{\frac{17}{4}}{5}=\frac{17}{4} \div \frac{5}{1}=\frac{17}{4} \times \frac{1}{5}=\frac{17}{20}$$
∴ Arithmetic Mean = $$\frac{17}{20}$$

Question 2.
Amounts donated by eight students to ‘NIVAR’ cyclone effected people are ₹300, ₹450, ₹700, ₹650, ₹400, ₹750, ₹900 and ₹850. Find the Arithmetic Mean of amounts donated.
Given data, ₹300, ₹450, ₹700, ₹650, ₹400, ₹750, ₹900 and ₹850.
Sum of observations = 300 + 450 + 700 +650 +400 + 750 + 900 + 850 = 5000
Number of observations = 8
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$ = $$\frac{5000}{8}$$ = ₹625
∴ Arithmetic Mean of amount donated = ₹625

Question 3.
The number of passengers who travelled in APSRTC bus from Eluru to Rangapuram in 5 trips in a day are 35, 42, 28, 41 and 44. What is the average of number of passengers travelled per trip ?

Given data are 35, 42, 28, 41, 44.
Sum of observations = 35 + 42 + 28 + 41 + 44 = 190
Number of observations = 5
∴ Arithmetic Mean (or) Average = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$ = $$\frac{190}{5}$$ = 38
∴Average of number of passengers travelled per trip = 38.

Question 4.
Find Arithmetic mean of factors of 24.
Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.
Sum of (factors) observations = 1 + 2 + 3 + 4 + 6 + 8+ 12 + 24 = 60
Number of observations = 8
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$ = $$\frac{60}{8}$$ = 7.5
∴ Arithmetic Mean of factors of 24 is 7.5

Question 5.
Find the Arithmetic Mean of x, x + 1 and x + 2.
∴ Arithmetic Mean = $$\frac{\text { Sum of observations }}{\text { Number of observations }}$$
= $$\frac{3 x+3}{3}$$ = $$\frac{3(x+1)}{3}$$