AP State Syllabus AP Board 6th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 11th Lesson Perimeter and Area Ex 11.3

Question 1.

Find the area of the rectangle of measurements 15 cm and 8 cm as length and breadth respectively.

Solution:

Given length of the rectangle l = 15 cm

breadth of the rectangle b = 8 cm

Area of the rectangle A = l x b

= 15 x 8 = 120 sq.cm

Question 2.

Find the area of a square whose perimeter is 64 m.

Solution:

Given perimeter of a square = 4 x side = 64 m

Divide with 4 on both sides,

\(\frac{4 \times \operatorname{side}}{4}=\frac{64}{4}\)

side (s) = 16 m

Area of the square = s.s = 16xl6 = 256 sq.m

Question 3.

Perimeters of a rectangle and square are equal. If the length of the rectangle is 14 cm and the perimeter of the square is 44 cm, find the area of the rectangle.

Solution:

Given the length of the rectangle l = 14 cm

breadth of the rectangle b = ?

Perimeter of the square = 44 cm

Given perimeter of the rectangle = Perimeter of the square ‘

2(l + b) = 44

2(14 + b) = 44

Divide with 2 on both sides,

\(\frac{2(14+b)}{2}=\frac{44}{2}\)

14 + b = 22

Subtract 14 on both sides,

14 + b – 14 = 22 – 14

Breadth of the rectangle b = 8 cm

Area of the rectangle = l x b = 14 x 8 = 112 sq. cm

Question 4.

Find the perimeters and areas of the following and answer the questions.

A) A rectangle with length and breadth as 16 cm and 8 cm respectively.

B) A rectangle with length and breadth as 14 cm and 10 cm respectively.

C) A square with side 12 cm.

(i) Which of the above perimeters are equal ?

(ii) Are all these areas equal? If not, which one has the bigger area?

Solution:

A) Given length of the rectangle l =16 cm

– Breadth of the rectangle b = 8 cm

Perimeter of the rectangle P = 2(1 + b)

= 2(16 + 8) = 2×24 = 48 cm

Area of the rectangle A = l x b

= 16 x 8 = 128 sq. cm

B) Given length of the rectangle l = 14 cm

Breadth of the rectangle b = 10 cm

Perimeter of the rectangle P = 2(l + b)

= 2(14 + 10) = 2 x 24 = 48 cm

Area of the rectangle A = l x b

= 14 x 10 = 140 sq.cm

C) Given side of the square s = 12 cm

Perimeter of the square P = 4 x s = 4 x 12 = 48 cm

Area of the square A = s x s = 12 x 12 = 144 sq. cm

i) Perimeters of rectangle A and rectangle B and square are equal.

ii) No. Areas are not equal and area of the square is greater than the areas of rectangles.