AP State Syllabus AP Board 8th Class Maths Solutions Chapter 3 Construction of Quadrilaterals Ex 3.2 Textbook Questions and Answers.

## AP State Syllabus 8th Class Maths Solutions 3rd Lesson Construction of Quadrilaterals Exercise 3.2

Construct quadrilateral with the measurements given below:

Question (a).

Quadrilateral ABCD with AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm andAC= 7cm

Solution:

In Quadrilateral ABCD with AB = 4.5 cm, BC = 5.5 cm, CD = 4 cm, AD = 6 cm and AC = 7 cm.

Construction Steps:

- Draw a line segment \(\overline{\mathrm{AB}}\) with radius 4.5 cms.
- With the centres A, B draw arcs equal to 7 cm and 5.5 cm respectively. The intersection of these two arcs keep as ‘C’.
- Join A, C and B, C.
- With centres C, A draw arcs equal to 4 cm, 6 cm respectively. These intersecting point is keep as ’D’.

Join D, C and A, D. - ∴ The required quadrilateral ABCD is formed.

Question (b).

Quadrilateral PQRS with PQ = 3.5 cm, QR = 4 cm, RS = 5 cm, PS = 4.5 cm and QS= 6.5 cm

Solution:

In a quadrilateral PQRS,

PQ = 3.5 cm, QR = 4 cm, RS = 5 cm,

PS – 4.5 cm, QS = 6.5 cm

Construction Steps:

- Draw a line segment \(\overline{\mathrm{PQ}}\) with radius 3.5 cm.
- With the centres P, Q draw arcs equal to 4.5 cm and 6.5 cm respectively.
- These two arcs meet at point ‘S’.
- With the centres S, Q draw arcs with radius 5 cm, 4 cm respectively. These two arcs intersected at point ‘R’.
- Join P, S; Q, S; S, R and Q, R.
- ∴ The required quadrilateral PQRS is formed.

Question (c).

Parallelogram ABCD with AB = 6cm, CD = 4.5 cm and BD = 7.5 cm

Solution:

In a parallelogram ABCD; AB = 6 cm, BC = 4.5 cm, BD = 7.5 cm

AB = CD (;cm

BC = AD = 4.5 cm

BD = 7.5 cm

Construction Steps:

- Draw a line segment \(\overline{\mathrm{AB}}\) with radius 6 cms.
- With the centres A, B draw arcs with radius 4.5 cm, 7.5 cm respectively. These two arcs meet at point ‘D’.
- With the centres D, B draw arcs with radius 6 cm, 4.5 cm respectively. These two arcs meet at point ‘C’.
- Join A, D and B, C and D, C and B, D.
- ∴ The required parallelogram ABCD is formed.

Question (d).

Rhombus NICE with NI = 4 cm and IE = 5.6 cm

Solution:

In a rhombus NI = IC = CE = NE = 4 cm, IE = 5.6 cm

Construction Steps:

- Draw a line segment \(\overline{\mathrm{NI}}\) with radius 4 cm.
- With the centres N, I draw two arcs with radius 4 cm, 5.6 cm respectively. These two arcs meet at point E’.
- With the centres E, I draw arcs with radius 4 cm. These two arcs meet at point ‘C’.
- Join N, E and I, E. Also join E, C and I, C.
- .’. The required rhombus NICE is formed.