{"id":9888,"date":"2021-04-12T11:08:04","date_gmt":"2021-04-12T05:38:04","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=9888"},"modified":"2021-09-15T11:34:12","modified_gmt":"2021-09-15T06:04:12","slug":"ap-board-7th-class-maths-solutions-chapter-6-ex-4","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-6-ex-4\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 6 Ratio – Applications Ex 4"},"content":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions<\/a> Chapter 6 Ratio – Applications Ex 4 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 6th Lesson Ratio – Applications Exercise 4<\/h2>\n

\"AP<\/p>\n

Question 1.
\nIn a school X, 48 students appeared for 10th class exam out of which 36 students passed. In another school Y, 30 students appeared and 24 students passed. If the District Educational Officer wants to give an award on the basis of pass percentage. To which school will he give the award?
\nSolution:
\nFrom the first school:
\nNumber of students appeared for the exam = 48
\nNumber of students passed = 36
\nas a percentage = \\(\\frac { 36 }{ 48 }\\) \u00d7 100 = 75
\nPass percentage = 75%<\/p>\n

From the second school:
\nNumber of students appeared = 30
\nNumber of students passed = 24
\nPass percentage = \\(\\frac { 24 }{ 30 }\\) \u00d7 100 = 80%
\nAs 80% > 75%
\nD.E.O should give award to the 2nd school.<\/p>\n

\"AP<\/p>\n

Question 2.
\nLast year the cost of 1000 articles was \u20b9 5000. This year it goes down to \u20b9 4000. What is the percentage of decrease in price?
\nSolution:
\nLast year
\nCost of 1000 articles = \u20b9 5000
\n\u2234 Cost of one article = \\(\\frac { 5000 }{ 1000 }\\) = \u20b9 5
\nThis year
\nCost of 1000 articles = \u20b9 4000
\n\u2234 Cost of one article = \\(\\frac { 4000 }{ 1000 }\\) = \u20b9 4
\nDecrease in price = \u20b9 5 – \u20b9 4 = \u20b9 1
\nDecrease In percentage = \\(\\frac { 1 }{ 5 }\\) \u00d7 100% = 20%<\/p>\n

Question 3.
\nSri Jyothi has a basket full of bananas, oranges and mangoes. If 50% are bananas, 15% are oranges, then what percent are mangoes?
\nSolution:
\nPercent of bananas = 50%
\nPercent of oranges = 15%
\n\u2234 Percent of mangoes = 100% – (50% + 15%)
\n= 100% – 65% = 35%<\/p>\n

\"AP<\/p>\n

Question 4.
\n64% + 20% + …..? = 100%
\nSolution:
\n(64% + 20%) +…………… = 100%
\n\u2234 ?=100% – 84% = 16%<\/p>\n

Question 5.
\nOn a rainy day, out of 150 students in a school 25 were absent. Find the percentage of students absent from the school? What percentage of students are present?
\nSolution:
\nTotal students = 150
\nNumber of students absent = 25
\n\u2234 Number of students present = 150 – 25 = 125
\n\"AP<\/p>\n

Question 6.
\nOut of 12000 voters in a constituency, 60% voted. Find hte number of people voted in the
\nconstituency?
\nSolution:
\nPercentage of people who voted = 60% of I 2,000
\n\u2234 Number of people voted = \\(\\frac{60 \\times 12000}{100}\\) = 7,200<\/p>\n

\"AP<\/p>\n

Question 7.
\nA local cricket team played 20 matches in one season. If it won 25% of them and lost rest. How many matches did it loose?
\nSolution:
\nTotal number of matches played = 20
\nMatches won = 25%
\n\u2234 Matches lost = (100 –\u00a0 25)% of total played
\n= 75% of 20
\n\\(\\frac{75 \\times 20}{100}\\) = 15<\/p>\n

Question 8.
\nIn every gram of gold, a goldsmith mixes 0.25 grams of silver and 0.05 grams of copper. What is the percentage of gold, silver and copper in every gram of gold?
\nSolution:
\nIn 1 gm
\nThe quantity of silver = 0.25 gm
\nThe quantity of copper = 0.05 gm
\n\u2234 The quantity of gold = 1 gm – (0.25 . 0.05)
\n= 1 – 0.3 = 0.7gm
\n\u2234 Percentage of gold = \\(\\frac { 0.7 }{ 1 }\\) \u00d7 100 = 70%
\n\u2234 Percentage of silver = \\(\\frac { 0.25 }{ 1 }\\) \u00d7 100 = 25%
\n\u2234 Percentage of copper = \\(\\frac { 0.05 }{ 2 }\\) \u00d7 100 = 5%<\/p>\n

\"AP<\/p>\n

Question 9.
\n40% of a number is 800 then find the number?
\nSolution:
\nLet the number be = x
\n40% of x = 800
\n(i.e.,) \\(\\frac{40 \\times x}{100}\\) = 800
\nx = \\(\\frac{800 \\times 100}{40}\\)
\nx = 2000
\n\u2234 The required number = 2000<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions Chapter 6 Ratio – Applications Ex 4 Textbook Questions and Answers. AP State Syllabus 7th Class Maths Solutions 6th Lesson Ratio – Applications Exercise 4 Question 1. In a school X, 48 students appeared for 10th class exam out of which 36 students passed. In another …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/9888"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=9888"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/9888\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=9888"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=9888"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=9888"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}