{"id":6523,"date":"2021-03-09T14:29:17","date_gmt":"2021-03-09T08:59:17","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=6523"},"modified":"2021-09-15T11:39:26","modified_gmt":"2021-09-15T06:09:26","slug":"ap-board-8th-class-maths-solutions-chapter-5-ex-5-1","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-8th-class-maths-solutions-chapter-5-ex-5-1\/","title":{"rendered":"AP Board 8th Class Maths Solutions Chapter 5 Comparing Quantities Using Proportion Ex 5.1"},"content":{"rendered":"

AP State Syllabus AP Board 8th Class Maths Solutions<\/a> Chapter 5 Comparing Quantities Using Proportion Ex 5.1 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 8th Class Maths Solutions 5th Lesson Comparing Quantities Using Proportion Exercise 5.1<\/h2>\n

\"AP<\/p>\n

Question 1.
\nFind the ratio of the following
\n(i) Smita works in office for 6 hours and Kajal works for 8 hours in her office. Find the
\nratio of their working hours.
\nSolution:
\nThe ratio of working hours of smita and kajal = 6:8
\n= (2 \u00d7 3 ) : (2 \u00d7 4) = 3 : 4<\/p>\n

(ii) One pot contains 8 litre of milk while other contains 750 milliliter.
\nSolution:
\n8lit : 750ml
\n8 \u00d7 1000 : 750
\n= \\([latex]\\frac { 8000 }{ 750 }\\)[\/latex] = 32 : 3<\/p>\n

(iii) speed of a cycle is 15km\/h and speed of the scooter is 30km\/h.
\nSolution:
\nThe ratio of speeds of a cycle and a sector
\n= 15 : 30 = (15 \u00d7 1) : 15 \u00d7 2 = 1 : 2<\/p>\n

\"AP<\/p>\n

Question 2.
\nIf the compound ratio of 5:8 and 3:7 is 45:x. Find the value of x.
\nSolution:
\nThe compound ratio of 5:8 and 3:7
\n= \\(\\frac{5}{8} \\times \\frac{3}{7}=\\frac{15}{56}\\)
\nAccording to the sum
\n15 : 56 = 45 : x
\n\u2234 x = 168<\/p>\n

Question 3.
\nIf the compound ratio of 7:5 and 8:x is 84:60. Find x.
\nSolution:
\nThe compound ratio of 7:5 and 8:x
\n= \\(\\frac{7}{5} \\times \\frac{8}{x}=\\frac{56}{5 x}\\)
\nAccording to the sum
\n56 : 5x = 84 : 60
\n\"AP
\n\u2234 x = 8<\/p>\n

Question 4.
\nThe compound ratio of 3:4 and the inverse ratio of 4:5 is 45:x. Find x.
\nSolution:
\nThe inverse ratio of 4:5 is 45 : x
\nThe compound ratio of 3:4 and 5 : 4
\n= 45 : x
\n\"AP
\n\u21d2 x = 16 \u00d7 3 = 48
\n\u2234 x = 48<\/p>\n

\"AP<\/p>\n

Question 5.
\nIn a primary school there shall be 3 teachers to 60 students. If there are 400 students
\nenrolled in the school, how many teachers should be there in the school in the same ratio?
\nSolution:
\nNo. of teachers are required for 400 students at the rate of 3 teachers to 60
\nstudents are \u21d2 60 : 3 400 : x
\n\"AP
\n\u2234 x = 20<\/p>\n

Question 6.
\nIn the given figure, ABC is a triangle. Write all possible ratios by A
\ntaking measures of sides pair wise.
\n8cm 10cm
\n(Hint: Ratio of AB : BC =8 : 6)
\n\"AP
\nSolution:
\n\"AP
\nIn \u0394ABC
\nAB : BC = 8 : 6 = 4:3
\n\u21d2 BC : AB = 6 : 8 = 3: 4
\nBC : CA = 6 : 10 = 3 : 5
\n\u21d2 CA : BC = 10 : 6 = 5 : 3
\nCA : AB = 10:8=5:4
\n\u21d2 AB : CA = 8: 10 = 4: 5<\/p>\n

\"AP<\/p>\n

Question 7.
\nIf 9 out of 24 students scored below 75% marks in a test. Find the ratio of student scored below 75% marks to the student scored 75% and above marks.
\nSolution:
\nOut of 24 students who got below 75% of marks = 9
\nWho got 75% and above marks =24 – 9 = 15
\n\u2234 The ratio between no. of students
\nwho got less than 75% of marks and
\nwho got 75% and above marks
\n= 9 : 15 =(3 \u00d7 3):(3 \u00d7 5) = 3 : 5<\/p>\n

Question 8.
\nFind the ratio of number of vowels in the word\u2019 MISSISSIPPI\u2019 to the number of consonants in the simplest form.
\nSolution:
\nNo. of vowels in the word MI S S SS! PPI = 4 (IIII)
\nNo. of consonants in that word = 7 (MSSSSPP)
\n\u2234 The ratio between vowels and consonants = 4: 7<\/p>\n

Question 9.
\nRajendra and Rehana own a business. Rehana receives 25% of the profit in each month. If
\nRehana received \u20b9 2080 in particular month, what is the total profit in that month?
\nSolution:
\nTotal Profit = x say
\n25% of x = 2080
\n\u21d2 \\(\\frac{25}{100}\\) \u00d7 x = 2080
\n\u21d2 \\(\\frac{x}{4}\\) = 2080
\n\u21d2 x = 2080 \u00d7 4
\n\u2234 x = \u20b9 8320<\/p>\n

\"AP<\/p>\n

Question 10.
\nIn triangle ABC, AB = 2.2 cm, BC = 1.5 cm and AC = 2.3 cm. In triangle XYZ, XY = 4.4cm, YZ = 3cm and XZ = 4.6cm. Find the ratio AB:XY, BC:YZ, AC:XZ. Are the lengths of corresponding sides of \u0394ABC and \u0394XYZ are in proportion?
\n[Hint : Any two triangles are said to be in proportion, if their corresponding sides are in the
\nsame ratio]
\nSolution:
\n\"AP
\n\u2234 The corresponding sides of both the triangles are in proportion.
\n\u2234 \u0394ABC ~ \u0394XYZ<\/p>\n

Question 11.
\nMadhuri went to a super market. The price changes are as follows. The price of rice reduced by 5% jam and fruits reduced by 8% and oil and dal increased by 10%. Help Madhuri to find the changed prices in the given table.<\/p>\n\n\n\n\n\n\n\n\n
Item<\/td>\nOriginal price\/kg<\/td>\nChanged price<\/td>\n<\/tr>\n
Rice<\/td>\n\u20b9 30<\/td>\n<\/td>\n<\/tr>\n
Jam<\/td>\n\u20b9 100<\/td>\n<\/td>\n<\/tr>\n
Apples<\/td>\n\u20b9 280<\/td>\n<\/td>\n<\/tr>\n
Oil<\/td>\n\u20b9 120<\/td>\n<\/td>\n<\/tr>\n
Dal<\/td>\n\u20b9 80<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Solution:<\/p>\n\n\n\n\n\n\n\n\n
Item<\/td>\nOriginal price\/kg<\/td>\nChanged price<\/td>\n<\/tr>\n
Rice<\/td>\n\u20b9 30<\/td>\n\u20b928.50<\/td>\n<\/tr>\n
Jam<\/td>\n\u20b9 100<\/td>\n\u20b9 92<\/td>\n<\/tr>\n
Apples<\/td>\n\u20b9 280<\/td>\n\u20b9 257.6<\/td>\n<\/tr>\n
Oil<\/td>\n\u20b9 120<\/td>\n\u20b9 132<\/td>\n<\/tr>\n
Dal<\/td>\n\u20b9 80<\/td>\n\u20b9 88<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\"AP<\/p>\n

Question 12.
\nThere were 2075 members enrolled in the club during last year. This year enrolment is
\ndecreased by 4%.
\n(a) Find the decrease in enrolment.
\n(b) How many members are enrolled during this year?
\nSolution:
\nNo. of persons are enrolled in the last year = 2075
\nPresent year no. of persons are enrolled
\n= 4% less than the previous year.
\na) Decrease in enrolment = 4% of 2075
\n\"AP<\/p>\n

b) No.of members are enrolled this
\nyear = 2075 – 4% of 2075
\n=2075 – 83 = 1992<\/p>\n

Question 13.
\nA farmer obtained a yielding of 1720 bags of cotton last year. This year she expects her crop to be 20% more. How many bags of cotton does she expect this year?
\nSolution:
\nDuring the last year yielding the bags of
\ncotton = 1720
\nIf she expects 20% crop to be more then
\n=20% of 1720 .
\n= \\(\\frac{20}{100}\\) \u00d7 1720
\n= 2 \u00d7 172
\n= 344 bags
\nHer expectation of total bags
\n= 1720 + 344
\n= 2064<\/p>\n

\"AP<\/p>\n

Question 14.
\nPoints P and Q are both in the line segment AB and on the same side of its midpoint. P divides AB in the ratio 2: 3, and Q divides AB in the ratio 3 :4. If PQ =2, then find the length of the line segment AB.
\nSolution:
\nGiven that \u2018C\u2019 is the midpoint of line segment AB.
\nHere \u2018P\u2019 divides AB inthe ratio 2 : 3
\n\u2018Q\u2019 divides AB in the ratio 3: 4
\n\"AP
\nPQ =2 cm [Given]
\nPQ = QB – PB
\n= 4 – 3 = 1 part = 2cm
\n\u2234 AB = AQ + QB [with respect to Ql
\nAB = AP+ PB [with respect to P]
\nL.C.M. of 5, 7 parts = 35 parts
\n\u2234 Length of AB 35 parts
\n= 35 \u00d7 2[ \u2235 part = 2cm]
\n= 70cm<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 8th Class Maths Solutions Chapter 5 Comparing Quantities Using Proportion Ex 5.1 Textbook Questions and Answers. AP State Syllabus 8th Class Maths Solutions 5th Lesson Comparing Quantities Using Proportion Exercise 5.1 Question 1. Find the ratio of the following (i) Smita works in office for 6 hours and Kajal works …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/6523"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=6523"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/6523\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=6523"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=6523"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=6523"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}