10th Class Maths 7th Lesson Coordinate Geometry Optional Exercise Textbook Questions and Answers<\/h3>\n
Question 1. Question 2. Question 3. Question 4. Question 5. AP State Syllabus SSC 10th Class Maths Solutions 7th Lesson Coordinate Geometry Optional Exercise AP State Board Syllabus\u00a0AP SSC 10th Class Maths Textbook Solutions Chapter 7 Coordinate Geometry Optional Exercise Textbook Questions and Answers. 10th Class Maths 7th Lesson Coordinate Geometry Optional Exercise Textbook Questions and Answers Question 1. Centre of the circle Q is …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/5728"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=5728"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/5728\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=5728"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=5728"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=5728"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nCentre of the circle Q is on the Y-axis. And the circle passes through the points (0, 7) and (0, -1). Circle intersects the positive X-axis at (p, 0). What is the value of \u2018p\u2019 ?
\nAnswer:
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-5-Quadratic-Equations-Optional-Exercise-20.png\")
\nGiven points A, B are on y – axis.
\n(\u2235 their x – coordinate is zero) then they will be the end points (0, 7) and (0, -1).
\nCentre (Q) = \\(\\left(\\frac{0+0}{2}, \\frac{7-1}{2}\\right)\\) = (0, 3)
\nthen radius = AQ = BQ
\n= \\(\\sqrt{(0-0)^{2}+(3-(-1))^{2}}\\)
\n= \\(\\sqrt{0^{2}+4^{2}}\\) = \u221a16 = 4
\nnow P(p, 0) is also another point on circle then \\(\\overline{\\mathrm{QP}}\\) is also radius
\n\u2234 \\(\\overline{\\mathrm{QP}}\\) = \\(\\sqrt{(0-p)^{2}+(3-0)^{2}}\\) = 4
\n\u21d2 \\(\\sqrt{p^{2}+3^{2}}\\) = 4
\n\u21d2 p2<\/sup> = 42<\/sup> – 32<\/sup> = 16 – 9 = 7
\n\u2234 P = \u00b1 \u221a7 .<\/p>\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\")
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\nA triangle ABC is formed by the points A(2, 3), B(-2, -3), C(4, -3). What is the point of intersection of side BC and angular bisector of angle A?
\nAnswer:
\nGiven: \u25b3ABC, where A (2, 3), B (- 2, – 3), C (4, – 3).
\nLet AD be the bisector to \u2220A meeting BC at D.
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-2.png\")
\nThen BD : DC = AB : AC
\n[\u2235 The bisector of vertical angle of triangle divides the base in the ratio of other two sides.]
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-3.png\")
\nNow D is a point which divides \\(\\overline{\\mathrm{BC}}\\) in the ratio \u221al3 : \u221a10 internally section formula (x, y) =
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-4.png\")
\n(By rationalising the denominator of the x-coordinate).<\/p>\n<\/p>\n
\nThe side BC of an equilateral \u25b3ABC is parallel to X – axis. Find the slopes of line along sides BC, CA and AB.
\nAnswer:
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-5.png\")
\nGiven: \u25b3ABC; BC \/\/ X – axis.
\nSlope of BC = tan \u03b8
\nwhere \u03b8 is the angle made of BC with + ve X – axis.
\n= tan \u20180\u2019 = ‘0\u2019
\nSlope of AB = tan 60\u00b0 = \u221a3
\n[\u2235 Each angle of an equilateral triangle is 60\u00b0]
\nSlope of AC = tan 60\u00b0 = \u221a3<\/p>\n
\nA right triangle has sides \u2018a\u2019 and ‘b’ where a > b. If the right angle is bisected then find the distance between ortho centres of the smaller triangles using coordinate geometry.
\nAnswer:
\nGiven : \u25b3ABC; \u2220B = 90\u00b0
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-6.png\")
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\nFind the centroid of the triangle formed by the line 2x + 3y – 6 = 0 with the coordinate axes.
\nAnswer:
\nGiven : \u25b3AOB formed by the line 2x + 3y – 6 = 0 with axes.
\nLet A lie on X – axis and B on Y – axis.
\n\u2234 Y – coordinate of A = 0
\nX – coordinate of B = 0
\n\u2234 A (3, 0), B (0, 2)
\n![\"AP](\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-SSC-10th-Class-Maths-Solutions-Chapter-7-Coordinate-Geometry-Optional-Exercise-7.png\")
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