{"id":5152,"date":"2021-03-04T09:35:17","date_gmt":"2021-03-04T04:05:17","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=5152"},"modified":"2021-09-15T11:39:30","modified_gmt":"2021-09-15T06:09:30","slug":"ap-board-9th-class-maths-solutions-chapter-13-ex-13-2","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-9th-class-maths-solutions-chapter-13-ex-13-2\/","title":{"rendered":"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2"},"content":{"rendered":"<p>AP State Syllabus\u00a0<a href=\"https:\/\/apboardsolutions.guru\/ap-board-9th-class-maths-solutions\/\">AP Board 9th Class Maths Solutions<\/a> Chapter 13 Geometrical Constructions Ex 13.2 Textbook Questions and Answers.<\/p>\n<h2>AP State Syllabus 9th Class Maths Solutions 13th Lesson Geometrical Constructions Exercise 13.2<\/h2>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>Question 1.<br \/>\nConstruct AABC in which BC = 7 cm,\u2220B = 75\u00b0 and AB + AC =12 cm.<br \/>\nSolution:<br \/>\nA.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5161\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-1.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 1\" width=\"163\" height=\"232\" \/><br \/>\nSteps:<\/p>\n<ul>\n<li>Draw a line segment BC = 7 cm.<\/li>\n<li>Erect \u2220B = 75\u00b0<\/li>\n<li>MarkapointDon \\(\\overrightarrow{\\mathrm{BX}}\\) suchthat BD = AB + AC.<\/li>\n<li>Join D, C and draw the perpendicular bisector of \\(\\overline{\\mathrm{CD}}\\) meeting BD at A.<\/li>\n<li>Join A to C to form the \u0394ABC.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>Question 2.<br \/>\nConstruct \u0394PQR in which QR = 8 cm, \u2220B = 60\u00b0 and AB &#8211; AC = 3.5 cm.<br \/>\nRead \u2220Q = 60\u00b0and PQ &#8211; PR = 3.5 cm<br \/>\nSolution:<br \/>\nA.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5160\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-2.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 2\" width=\"412\" height=\"244\" srcset=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-2.png 412w, https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-2-300x178.png 300w\" sizes=\"(max-width: 412px) 100vw, 412px\" \/><br \/>\nSteps: I<\/p>\n<ul>\n<li>Draw QR = 8 cm.<\/li>\n<li>Construct \u2220RQX = 300 at Q.<\/li>\n<li>Mark a point S on \\(\\overrightarrow{\\mathrm{QX}}\\) such that QS = PQ\u00a0 &#8211;\u00a0 PR = 3.5 cm.<\/li>\n<li>Join S, R and draw the perpendicular bisector to \\(\\overline{\\mathrm{QR}}\\) meeting \\(\\overrightarrow{\\mathrm{QX}}\\) at P.<\/li>\n<li>Join P, R to form the \u0394PQR.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>Question 3.<br \/>\nConstruct \u0394XYZ in which \u2220Y = 30 \u00b0; \u2220Z = 60 \u00b0 and XY + YZ + ZX = 10 cm.<br \/>\nSolution:<br \/>\nA.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5159\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-3.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 3\" width=\"361\" height=\"313\" srcset=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-3.png 361w, https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-3-300x260.png 300w\" sizes=\"(max-width: 361px) 100vw, 361px\" \/><br \/>\nSteps:<\/p>\n<ul>\n<li>Draw a line segment AB = XY + YZ + ZX = 10 cm.<\/li>\n<li>Construct \u2220BAP = \\(\\frac { 1 }{ 2 }\\) \u2220Y at A and \u2220ABQ = \\(\\frac { 1 }{ 2 }\\) \u2220Z at B meeting at X.<\/li>\n<li>Draw the perpendicular bisectors to XA and XB meeting \\(\\overline{\\mathrm{AB}}\\) at Y and Z respectively.<\/li>\n<li>Join X to Y and Z to form the \u0394XYZ.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>Question 4.<br \/>\nConstruct a right triangle whose base is 7.5 cm and sum of its hypotenuse and otherside is 15 cm.<br \/>\nSolution:<br \/>\nA.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5158\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-4.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 4\" width=\"248\" height=\"304\" srcset=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-4.png 248w, https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-4-245x300.png 245w\" sizes=\"(max-width: 248px) 100vw, 248px\" \/><br \/>\nSteps:<\/p>\n<ul>\n<li>Draw BC = 7.5 cm.<\/li>\n<li>Construct \u2220CBX = 90\u00b0<\/li>\n<li>Mark a point D on \\(\\overrightarrow{\\mathrm{BX}}\\) such that BD = 15 cm.<\/li>\n<li>Join C, D. \u2018<\/li>\n<li>Draw the perpendicular bisectors of \\(\\overline{\\mathrm{CD}}\\) meeting BD at A.<\/li>\n<li>Join A, C to form the \u0394ABC.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>Question 5.<br \/>\nConstruct a segment of a circle on a chord of length 5 cm containing the following angles i) 90\u00b0 ii) 45\u00b0 iii) 120\u00b0<br \/>\nSolution:<br \/>\ni) 90\u00b0<br \/>\nA.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5157\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-5.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 5\" width=\"259\" height=\"251\" \/><br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5156\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-6.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 6\" width=\"156\" height=\"135\" \/><\/p>\n<p>Steps:<\/p>\n<ul>\n<li>Draw a rough sketch of \u2220BAC = 90\u00b0 and \u2220BOC = 180\u00b0.<\/li>\n<li>Draw a line segment BC = 5 cm.<\/li>\n<li>Draw the perpendicular bisector of BC meeting \\(\\overline{\\mathrm{BC}}\\) at O<\/li>\n<li>Draw an arc of radius OB or OC with centre O.<\/li>\n<li>Mark any point A on the arc and join it with B and C.<\/li>\n<li>\u2220BAC = 90\u00b0<\/li>\n<\/ul>\n<p>ii) 45\u00b0<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5155\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-7.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 7\" width=\"303\" height=\"255\" srcset=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-7.png 303w, https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-7-300x252.png 300w\" sizes=\"(max-width: 303px) 100vw, 303px\" \/><br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5154\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-8.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 8\" width=\"157\" height=\"143\" \/><\/p>\n<p>Steps:<\/p>\n<ul>\n<li>Draw a line segment BC = 5 cm.<\/li>\n<li>Construct ABOC such that BC = 5 cm, \u2220B = 45\u00b0 = \u2220C.<\/li>\n<li>Draw a circle segment of radius OB or OC with centre \u2019O&#8217;.<\/li>\n<li>Mark any point A on the segment and join it with B and C.<\/li>\n<li>\u2220BAC = 45\u00b0<\/li>\n<\/ul>\n<p><img loading=\"lazy\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2020\/12\/AP-Board-Solutions.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2\" width=\"196\" height=\"17\" \/><\/p>\n<p>iii) 120\u00b0<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-5153\" src=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-9.png\" alt=\"AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 9\" width=\"309\" height=\"249\" srcset=\"https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-9.png 309w, https:\/\/apboardsolutions.guru\/wp-content\/uploads\/2021\/03\/AP-Board-9th-Class-Maths-Solutions-Chapter-13-Geometrical-Constructions-Ex-13.2-9-300x242.png 300w\" sizes=\"(max-width: 309px) 100vw, 309px\" \/><\/p>\n<p>Steps:<\/p>\n<ul>\n<li>Draw a line segment AB = 5 cm. ,<\/li>\n<li>Construct \u0394AOB in which \u2220A = 30\u00b0; \u2220B = 30\u00b0; AB = 5 cm.<\/li>\n<li>With &#8216;O&#8217; as centre draw a circle segment.<\/li>\n<li>On the opposite side make any point C and join it with B and C.<\/li>\n<li>\u2220ACB = 120\u00b0<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>AP State Syllabus\u00a0AP Board 9th Class Maths Solutions Chapter 13 Geometrical Constructions Ex 13.2 Textbook Questions and Answers. AP State Syllabus 9th Class Maths Solutions 13th Lesson Geometrical Constructions Exercise 13.2 Question 1. Construct AABC in which BC = 7 cm,\u2220B = 75\u00b0 and AB + AC =12 cm. Solution: A. Steps: Draw a line &hellip;<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[5],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/5152"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=5152"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/5152\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=5152"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=5152"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=5152"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}