{"id":22686,"date":"2022-01-18T15:04:15","date_gmt":"2022-01-18T09:34:15","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=22686"},"modified":"2022-01-18T15:04:15","modified_gmt":"2022-01-18T09:34:15","slug":"ap-board-7th-class-maths-solutions-chapter-11-ex-11-3","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-11-ex-11-3\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 11 Area of Plane Figures Ex 11.3"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 11 Area of Plane Figures Ex 11.3 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 11th Lesson Area of Plane Figures Ex 11.3<\/h2>\n

Question 1.
\nThe diameter of round table upper surface in Science lab is 70 cm. Find the area.
\n\"AP
\nAnswer:
\nGiven diameter of table d = 70 cm
\nRadius of table r = \\(\\frac{\\mathrm{d}}{2}\\) = \\(\\frac{70}{2}\\) = 35 cm
\nArea of the table = \u03c0r2<\/sup>
\n\"AP
\n\u2234 Area of the round table = 3,850 sq.cm.<\/p>\n

\"AP<\/p>\n

Question 2.
\nRadius of the circular shaped wall painting is 14 cm. Calculate the area of wall painting.
\n\"AP
\nAnswer:
\nGiven radius of the wall painting
\nr = 14 cm
\nArea of the circle = \u03c0r2<\/sup>
\n= \\(\\frac{22}{7}\\) \u00d7 142<\/sup>
\n\"AP
\n= 616
\n\u2234 Area of the wall painting = 616 sq.cm<\/p>\n

Question 3.
\nIf the area of circular shaped dart board is 1386 sq.cm. Find its radius and diameter.
\n\"AP
\nAnswer:
\nGiven the area of circular shaped dart board = 1386 sq.cm
\nArea of the circle = \u03c0r2<\/sup> = 1386
\n\u21d2 \\(\\frac{22}{7}\\) \u00d7 r2<\/sup> = 1386
\n\u21d2 22 \u00d7 r2<\/sup> = 1386 \u00d7 7
\n\"AP
\n\u21d2 r2<\/sup> = 441 = 212<\/sup>
\n\u21d2 r2<\/sup> = 212<\/sup>
\n\u2234 Radius of dart board r = 21 cm
\nDiameter of dart board d 2r
\n= 2 \u00d7 21
\n= 42 cm<\/p>\n

\"AP<\/p>\n

Question 4.
\nCircumference of the circular shaped clock is 44 cm. Find the radius and surface area of the clock.
\n\"AP
\nAnswer:
\nGiven the circumference of clock = 44 cm
\n\u21d2 2\u03c0r = 44 cm
\n\u21d2 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 r = 44
\n\u21d2 44 \u00d7 r = 44 \u00d7 7
\n\"AP
\n\u2234 Radius of the clock r = 7 cm
\nSurface area of the clock = \u03c0r2<\/sup>
\n= \\(\\frac{22}{7}\\) \u00d7 72<\/sup>
\n\"AP
\n\u2234 Surface area of the clock = 154 sq.cm<\/p>\n

\"AP<\/p>\n

Question 5.
\nThe circumference of a circular shaped lawn in a park is 352 m. Find the area of the circular shaped lawn. If cost of grass per sq. m is \u20b9 30, then find total cost of laying grass on lawn.
\n\"AP
\nAnswer:
\nGiven the circumference of lawn = 352 m
\n\u21d2 2\u03c0r = 352 m
\n\u21d2 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 r = 352
\n\u21d2 44r = 352 \u00d7 7 7
\n\"AP
\n\u2234 Radius of the lawn r = 56 m
\nArea of the lawn = \u03c0r2<\/sup>
\n= \\(\\frac{22}{7}\\) \u00d7 562<\/sup>
\n\"AP
\nArea of the lawn = 9856 sq.m
\nCost of grass per sq.m = \u20b9 30
\nCost of grass per 9856 sq.m = 9856 \u00d7 30
\n\u2234 Total cost of laying grass on lawn = \u20b9 2,95,680<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 11 Area of Plane Figures Ex 11.3 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 11th Lesson Area of Plane Figures Ex 11.3 Question 1. The diameter of round table upper surface in Science lab is 70 cm. Find the area. Answer: Given diameter …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22686"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=22686"}],"version-history":[{"count":3,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22686\/revisions"}],"predecessor-version":[{"id":22701,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22686\/revisions\/22701"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=22686"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=22686"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=22686"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}