{"id":22250,"date":"2022-01-14T16:51:34","date_gmt":"2022-01-14T11:21:34","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=22250"},"modified":"2022-01-14T16:51:34","modified_gmt":"2022-01-14T11:21:34","slug":"ap-board-7th-class-maths-solutions-chapter-8-ex-8-1","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-8-ex-8-1\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 8 Exponents and Powers Ex 8.1"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 8 Exponents and Powers Ex 8.1 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 8th Lesson\u00a0Exponents and Powers Ex 8.1<\/h2>\n

Questions 1.
\nExpress the following into exponential form:.
\n(i) 14 \u00d7 14 \u00d7 14
\nAnswer:
\n14 \u00d7 14 \u00d7 14 = 143<\/p>\n

(ii) 25 \u00d7 25 \u00d7 25 \u00d7 25 \u00d7 25
\nAnswer:
\n25 \u00d7 25 \u00d7 25 \u00d7 25 \u00d7 25 = 25<\/p>\n

(iii) ab \u00d7 ab \u00d7 ab \u00d7 ab
\nAnswer:
\nab \u00d7 ab \u00d7 ab \u00d7 ab = (ab)4<\/sup><\/p>\n

(iv) 7 \u00d7 p \u00d7 p \u00d7 q
\nAnswer:
\n7 \u00d7 p \u00d7 p \u00d7 q = 7 \u00d7 p2<\/sup> \u00d7 q<\/p>\n

\"AP<\/p>\n

Question 2.
\nExpress the following into expanded form:
\n(i) 276<\/sup>
\nAnswer:
\n276<\/sup> = 27 \u00d7 27 \u00d7 27 \u00d7 27 \u00d7 27 \u00d7 27<\/p>\n

(ii) 1015<\/sup>
\nAnswer:
\n1015 = 101 \u00d7 101 \u00d7 101 \u00d7 101 \u00d7 101<\/p>\n

(iii) (2b)4<\/sup>
\nAnswer:
\n2b4<\/sup> = 2b \u00d7 2b \u00d7 2b \u00d7 2b<\/p>\n

(iv) 3a8<\/sup>
\nAnswer:
\n3a8<\/sup> = 3 \u00d7 a\u00d7 a \u00d7 a \u00d7 a \u00d7 a \u00d7 a \u00d7 a \u00d7 a<\/p>\n

Question 3.
\nExpress the following In exponential form through prime factorisation: .
\n(i) 81
\nAnswer:
\n\"AP<\/p>\n

81 = 3 \u00d7 27
\n= 3 \u00d7 3 \u00d7 9
\n= 3 \u00d7 3 \u00d7 3 \u00d7 3
\n\u2234 81 = 34<\/sup><\/p>\n

(ii) 125
\nAnswer:
\n\"AP
\n125 = 5 \u00d7 25
\n= 5 \u00d7 5 \u00d7 5
\n\u2234 125 = 53<\/sup><\/p>\n

(iii) 324
\nAnswer:
\n\"AP
\n324 = 2 \u00d7 162
\n= 2 \u00d7 2 \u00d7 81
\n= 2 \u00d7 2 \u00d7 3 \u00d7 11
\n= 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 9
\n= 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3
\n\u2234 324 = 22<\/sup> \u00d7 34<\/sup><\/p>\n

(iv) 1080
\nAnswer:
\n\"AP
\n1080 = 2 \u00d7 540
\n= 2 \u00d7 2 \u00d7 270
\n= 2 \u00d7 2 \u00d7 2 \u00d7 135
\n= 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 45
\n= 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 15
\n= 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 5
\n\u2234 1080 = 23<\/sup> \u00d7 31<\/sup> \u00d7 51<\/sup><\/p>\n

\"AP<\/p>\n

Question 4.
\nCompute and identify the greater num-ber in the following pairs : 7
\n(i) 25<\/sup> or 52<\/sup>
\nAnswer:
\n25<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 32
\n52<\/sup> = 5 \u00d7 5 = 25
\n32 > 25
\nTherefore, 25<\/sup> > 52<\/sup><\/p>\n

(ii) 73<\/sup> or 37<\/sup>
\nAnswer:
\n73<\/sup> = 7 \u00d7 7 \u00d7 7 = 343
\n37<\/sup> = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 = 2187
\n2187 > 343
\nTherefore, 37<\/sup> > 73<\/sup><\/p>\n

(iii) 23<\/sup> or 32<\/sup>
\nAnswer:
\n23<\/sup> = 2 \u00d7 2 \u00d7 2 = 8
\n32<\/sup> = 3 \u00d7 3 = 9
\n9 > 8
\nTherefore, 32<\/sup> > 23<\/sup><\/p>\n

Question 5.
\nExpand 33<\/sup> \u00d7 42<\/sup> and 43<\/sup> \u00d7 32<\/sup>. Are they equal? Justify.
\nAnswer:
\n33<\/sup> \u00d7 42<\/sup> = 3 \u00d7 3 \u00d7 3 \u00d7 4 \u00d7 4
\n= 27 \u00d7 16 = 432<\/p>\n

43<\/sup> \u00d7 32<\/sup> = 4 \u00d7 4 \u00d7 4 \u00d7 3 \u00d7 3
\n= 64 \u00d7 9 = 576<\/p>\n

432 \u00d7 576 (They are not equal)
\nTherefore, 576 > 432
\nSo, 43<\/sup> \u00d7 32<\/sup> > 33<\/sup> \u00d7 42<\/sup><\/p>\n

Question 6.
\nExpress the following numbers in exponential form with the given base.
\n(i) 1000, base 10
\nAnswer:
\n\"AP
\n\u2234 1000 = 10 \u00d7 10 \u00d7 10 = 103<\/sup><\/p>\n

(ii) 512 base 2
\nAnswer:
\n\"AP
\n512 = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2
\n\u2234 512 = 29<\/sup><\/p>\n

(iii) 243 base 3
\nAnswer:
\n\"AP
\n243 = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3
\n\u2234 243 = 35<\/sup><\/p>\n

\"AP<\/p>\n

Question 7.
\nIf a = 2, b = 3 find the value of
\n(i) aa<\/sup> + bb<\/sup>
\nAnswer:
\nGiven a = 2, b = 3
\naa<\/sup> + bb<\/sup> = 22<\/sup> + 33<\/sup>
\n= (2 \u00d7 2) + (3 \u00d7 3 \u00d7 3)
\n= 4 + 27 = 31
\nTherefore, if a = 2, b = 3 then aa<\/sup> + bb<\/sup> = 31<\/p>\n

(ii) ab<\/sup> + ba<\/sup>
\nAnswer:
\nGiven a = 2, b = 3
\nab<\/sup> + ba<\/sup> = 23<\/sup> + 32<\/sup>
\n= (2 \u00d7 2 \u00d7 2) + (3 \u00d7 3).
\n= 8 + 9 = 17
\nTherefore, if a = 2, b = 3
\nthen ab<\/sup> + ba<\/sup> = 17<\/p>\n

(iii) (a + b)b<\/sup>
\nAnswer:
\nGiven a = 2, b = 3
\n(a + b)b<\/sup> = (2 + 3)3<\/sup> = 53<\/sup>
\n= 5 \u00d7 5 \u00d7 5 = 125
\nTherefore, if a = 2, b == 3
\nthen (a + b)b<\/sup> =125<\/p>\n

Question 8.
\nWrite the following in Exponential form:
\n(i) The speed of light in vacuum is about 30,00,00,000 m\/sec.
\nAnswer:
\nGiven the speed of light = 30,00,00,000 m\/sec
\n= 3 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n\u2234 Speed of light = 3 \u00d7 108<\/sup> m\/sec.<\/p>\n

(ii) The population of India is about 121,00,00,000 as per 2011 census.
\nAnswer:
\nGiven population of India
\n= 121,00,00,000
\n= 121 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n= 11 \u00d7 11 \u00d7 107<\/sup>
\n\u2234 Population of India = 112<\/sup> \u00d7 107<\/sup> as per 2011 census.<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 8 Exponents and Powers Ex 8.1 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 8th Lesson\u00a0Exponents and Powers Ex 8.1 Questions 1. Express the following into exponential form:. (i) 14 \u00d7 14 \u00d7 14 Answer: 14 \u00d7 14 \u00d7 14 = 143 (ii) 25 …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22250"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=22250"}],"version-history":[{"count":4,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22250\/revisions"}],"predecessor-version":[{"id":22294,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/22250\/revisions\/22294"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=22250"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=22250"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=22250"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}