{"id":21889,"date":"2022-01-13T16:18:55","date_gmt":"2022-01-13T10:48:55","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=21889"},"modified":"2022-01-13T16:18:55","modified_gmt":"2022-01-13T10:48:55","slug":"ap-board-7th-class-maths-solutions-chapter-7-review-exercise","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-7-review-exercise\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 7 Ratio and Proportion Review Exercise"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 7 Ratio and Proportion Review Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 7th Lesson Ratio and Proportion Review Exercise<\/h2>\n

Question 1.
\nFind the ratio of the following :
\n(i) 5,8
\nAnswer:
\n5 : 8<\/p>\n

(ii) \u20b9 10, \u20b9 15
\nAnswer:
\n10 : 15
\n2 : 3
\n\u2234 \u20b9 10 : \u20b915 = 2 : 3<\/p>\n

(iii) 25 kg., 20. kg.
\nAnswer:
\n25 kg : 20 kg
\n25 : 20
\n5 : 4
\n\u2234 25 kg : 20 kg = 5 : 4<\/p>\n

(iv) 5l, 500ml
\nAnswer:
\n5l : 500 ml
\n5000 ml: 500 ml (\u2235 1l = 1000 ml, 5l = 5000 ml)
\n5000 : 500
\n10 : 1
\n\u2234 5l : 500 ml = 10 : 1<\/p>\n

(v) 2 km. 500 m, 1 km. 750 m
\nAnswer:
\n2 km. 500 m : 1 km. 750 m
\n2000 m + 500 m : 1000 m + 750 m (\u2235 1 km = 1000m; 2 km = 2000 m)
\n2500 : 1750
\n10 : 7 (\u2235 HCF = 25)
\n\u2234 2 km. 500 m : 1 km. 750 m = 10 : 7<\/p>\n

(vi) 3 hrs, 1 hr. 30 min.
\nAnswer:
\n3 hrs : 1 hr. 30 min
\n3 \u00d7 60 : (1 \u00d7 60) + 30 (\u2235 1 hr = 60 min; 3h = 3 \u00d7 60 = 180 min)
\n180 min : 60 + 30 min
\n\"AP
\n2 : 1
\n\u2234 3 hrs : 1 hr. 30 min = 2:1<\/p>\n

(vii) 40 days, 1 year
\nAnswer:
\n40 days : 1 year
\n40 days : 365 days (\u2235 1 year = 365 days)
\n40 : 365 (\u2235 HCF = 5)
\n8 : 73<\/p>\n

\u2234 40 days : 1 year = 8 : 73
\n(Or)
\n40 days : 366 days (\u2235 1 year = 366 days for leap year)
\n20 : 183 (\u2235 HCF = 2)<\/p>\n

\"AP<\/p>\n

Question 2.
\nExpress the following ratios in the simplest form:
\n(i) 120 : 130
\nAnswer:
\nGiven 120 : 130
\n\"AP
\n12 : 13
\n\u2234 120 : 130 = 12 : 13<\/p>\n

(ii) 135:90
\nAnswer:
\nGiven 135 : 90
\n27 : 18
\n3 : 2
\n\u2234 135 : 90 = 3 : 2<\/p>\n

(iii) 48 : 144
\nAnswer:
\nGiven 48: 144
\n12 : 36
\n1 : 3
\n\u2234 48 : 144 = 1:3<\/p>\n

(iv) 81 : 54
\nAnswer:
\nGiven 81 : 54
\n9 : 6
\n3 : 2
\n\u2234 81 : 54 = 3 : 2<\/p>\n

(v) 432 : 378
\nAnswer:
\nGiven 432 : 378
\n216 : 189
\n24 : 21
\n8 : 7
\n\u2234 432 : 378 = 8 : 7<\/p>\n

\"AP<\/p>\n

Question 3.
\nCheck whether the two ratios given below are in proportion.<\/p>\n

(i) 10 : 20, 25 : 50
\nAnswer:
\nGiven 10 : 20, 25 : 50
\na :b = 10 : 20
\nSo, a : b = 1 : 2<\/p>\n

c : d = 25 : 50
\nalso, c : d = 1 : 2<\/p>\n

If a : b = c: d, then a, b, c, d are in proportion.
\na : b = c : d = 1 : 2
\nTherefore, 10 : 20, 25 : 50 are in proportion.<\/p>\n

(ii) 18 : 12, 15 : 10
\nAnswer:
\nGiven 18 : 12, 15 : 10
\na : b = 18 : 12
\n= 6 : 4<\/p>\n

c : d = 15 : 10
\nalso c : d = 3 : 2
\nSo, a : b = 3 : 2<\/p>\n

If a : b = c : d, then a, b, c, d are in proportion.
\na : b = c : d = 3 : 2
\nTherefore, 18 : 12, 15 : 10 are in proportion.<\/p>\n

(iii) 25 : 20, 16 : 14
\nAnswer:
\nGiven 25 : 20, 16 : 14
\na : b = 25 : 20
\nSo, a : b = 5 : 4
\n5 : 4 \u2260 8 : 7
\n\u2234 a : b \u2260 c : d<\/p>\n

c : d = 16 : 14
\nc : d = 8 : 7<\/p>\n

If a : b = c : d, then a, b, c, dare in propottion.
\nHere a : b \u2260 c : d
\nSo, a, b, c, d are not in proportion.<\/p>\n

(iv) 54 : 27, 18 : 9
\nAnswer:
\nGiven 54 : 27, 18 : 9
\na : b = 54 : 27.
\n= 6 : 3
\nSo, a : b = 2 : 1<\/p>\n

c : d = 18 : 9
\nalso, c : d = 2 : 1<\/p>\n

If a : b = c : d, then a, b, c, d are in proportion.
\na : b = c : d = 2 : 1<\/p>\n

Therefore, 54: 27, 18 : 9 are in proportion.<\/p>\n

Question 4.
\nFind the missing number in each of the following problems:
\n(i) 15 : 19 = 45 : _______
\nAnswer:
\nGiven 15 : 19 = 45 : x<\/span>
\nLet the missing term be \u2018x\u2019.
\nIf a : b = c : d, then a, b, c and d are in proportion, then the product of extremes is equal to the product of means that is a . d = b . c
\n\u21d2 15 \u00d7 x = 19 \u00d7 45
\n\"AP
\n\u21d2 x = 19 \u00d7 3
\n\u2234 x = 57<\/p>\n

(ii) 9 : 13 = ____ : 65
\nAnswer:
\nGiven 9 : 13 = x<\/span> : 65
\nLet the missing term be ‘x’.
\nIf a : b = c : d, then a, b, c and d are in proportion, then the product of extremes is equal to the product of means that is a . d = b . c
\n\u21d2 9 \u00d7 65 = 13 \u00d7 x
\n\"AP
\n\u21d2 45 = x
\n\u2234 x = 45<\/p>\n

(iii) 8 : ______ = 72 : 63
\nAnswer:
\nGiven 8 : x<\/span> = 72 : 63
\nLet the missing term be ‘x’.
\nIf a : b = c : d, then a, b, c and d are in proportion, then the product of extre\u00acmes is equal to the product of means that is a . d = b . c
\n\u21d2 8 \u00d7 63 = x \u00d7 72
\n\"AP
\n\u21d2 7 = x
\n\u2234 x = 7<\/p>\n

\"AP<\/p>\n

Question 5.
\nFill in the boxes with equivalent ratio of 3 : 4.
\n\"AP
\nAnswer:
\nGiven a : b = 3 : 4 (or) \\(\\frac{3}{4}\\)
\n\\(\\frac{a}{b}=\\frac{3}{4}\\)<\/p>\n

Equivalent ratios
\n\"AP
\nTherefore, a : b = 3 : 4 = 6 : 8
\n= 9 : 12 = 12 : 16 = 15 : 20 = 18 : 24
\n\"AP<\/p>\n

Question 6.
\nPick out any four numbers from below and arrange them so that they are in proportion 2, 3, 10, 12> 15, 18.
\nEx : 2 : 10 = 3 : 15
\n(i) : __________
\nAnswer:
\n2 : 3; 12 : 18
\na : b = 2 : 3, c : d = 12: 18
\nIf a, b, C, d are in proportion, then the product of extremes is equal to the pro\u00acduct of means.
\n\"AP
\na . d = b . c
\n2 \u00d7 18 = 3 \u00d7 12
\n36 = 36
\nSo, 2 : 3 = 12 : 18<\/p>\n

(ii) : __________
\nAnswer:
\n10 : 12 = 15 : 18
\na : b = 10 : 12
\nc : d = 15 : 18
\nIf a, b, c, d are in proportion, then the product of extremes is equal to the product of means.
\n\"AP
\na . d = b . c
\n10 \u00d7 18 = 15 \u00d7 12
\n180 = 180
\nSo, 10 : 12 = 15 : 18<\/p>\n

Question 7.
\nDivide \u20b9 1500 into two parts such that they are in the ratio of 7 : 3.
\nAnswer:
\nGiven amount to be divide = \u20b9 1500 .
\nRatio to be divide = 7:3
\nSum of the terms in the ratio = 7 + 3 = 10
\n\"AP
\n[Or 1500 – 1050 = 450]<\/p>\n

\"AP<\/p>\n

Question 8.
\nIf there are 20 chocolates in a packet, Rajani and Ragini share them and Rajani takes 12 chocolates, then what is the ratio of chocolates taken by Rajani to Ragini?
\nAnswer:
\nTotal number of Chocolates = 20
\nNumber of chocolates Rajani taken = 12
\nNumber of chocolates Ragini taken = 20 – 12 = 8
\nRatio of Rajani to Ragini = 12 : 8
\nRatio of chocolates taken by Rajani to Ragini = 3 : 2<\/p>\n

Question 9.
\nA pipe is cut into two parts in such a ratio that the first part to second part is 7:8. If the length of the 2nd part is 48cm, then what is the length of the first part? What is the total length of the pipe before cutting?
\nAnswer:
\nGiven ratio of two parts of pipe = 7:8
\nLength of the second part = 48 cm
\nLength of the first part = x cm
\nRatio of the two parts = x : 48
\n\"AP
\nProduct of extremes = Product of means
\n\u21d2 8 \u00d7 x = 48 \u00d7 7
\n\"AP
\n\u21d2 x = 42
\n\u2234 Length of first part of the pipe = x = 42 cm
\nLength of the pipe = 42 + 48 = 90 cm<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 7 Ratio and Proportion Review Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 7th Lesson Ratio and Proportion Review Exercise Question 1. Find the ratio of the following : (i) 5,8 Answer: 5 : 8 (ii) \u20b9 10, \u20b9 15 Answer: 10 : 15 2 …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21889"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=21889"}],"version-history":[{"count":5,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21889\/revisions"}],"predecessor-version":[{"id":21990,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21889\/revisions\/21990"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=21889"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=21889"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=21889"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}