{"id":21549,"date":"2022-01-11T17:20:45","date_gmt":"2022-01-11T11:50:45","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=21549"},"modified":"2022-01-28T10:06:30","modified_gmt":"2022-01-28T04:36:30","slug":"ap-board-7th-class-maths-solutions-chapter-3-ex-3-1","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-3-ex-3-1\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 3 Simple Equations Ex 3.1"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 3 Simple Equations Ex 3.1 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 3rd Lesson Simple Equations Exercise 3.1<\/h2>\n

Question 1.
\nWrite the equations of the following mathematical statements.
\n(i) A number x decreased by 5 is 14.
\nAnswer:
\nGiven number = x
\nNumber decreased by 5 = x – 5
\n\u2234 x – 15 = 14.<\/p>\n

\"AP<\/p>\n

(ii) Eight times of y plus 3 is -5.
\nAnswer:
\nGiven number = y
\nEight times of y = 8 \u2219 y
\nEight times of y plus 3 = 8y + 3
\n\u2234 8y + 3 = – 5<\/p>\n

(iii) If you add one fourth of z to 3 you get 7.
\nAnswer:
\nGiven number = z
\nOne fourth of z = \\(\\frac{1}{4}\\) \u2219 z = \\(\\frac{z}{4}\\)
\nOne fourth of z is added to 3 = \\(\\frac{z}{4}\\) + 3
\nResult is 7
\n\u2234 \\(\\frac{z}{4}\\) + 3 = 7.<\/p>\n

(iv) If you take away 5 from 3 times of m, you get 11.
\nAnswer:
\nGiven number = m
\n3 times of m = 3m
\nTake away 5 from 3 times of m = 3m – 5
\nResult is 11
\n\u2234 3m – 5 = 11<\/p>\n

(v) Sum of angles 2x, (x – 30) is a right angle.
\nAnswer:
\nGiven angles 2x, (x – 30)
\nSum of angles 2x, (x – 30)
\n= 2x + x – 30 = 3x – 30
\nSum of angles is right angle (90\u00b0).
\n\u2234 3x – 30 = 90\u00b0<\/p>\n

(vi) The perimeter of a square of side \u2018a\u2019 is 14 m.
\nAnswer:
\nGiven side of a square = a
\nPerimeter = 4 \u2219 side = 4 \u2219 a
\nGiven perimeter = 14 m
\n\u2234 4a = 14 m<\/p>\n

\"AP<\/p>\n

Question 2.
\nWrite the following equations in statement form.
\n(i) m – 5 = 12
\nAnswer:
\nA number m is decreased by 5 is 12.<\/p>\n

(ii) \\(\\frac{\\mathbf{a}}{\\mathbf{3}}\\) = 4
\nAnswer:
\nOne third of a is 4.<\/p>\n

(iii) 4x + 7 = 15
\nAnswer:
\nSum of 4 times of x and 7 is 15.
\n(or)
\n7 is added to 4 times of x is 15.<\/p>\n

(iv) 2 – 3y = 11
\nAnswer:
\n2 is decreased by 3 times of y is 11.
\n(or)
\n3 times of y is subtracted from 2 is 11.<\/p>\n

Question 3.
\nCheck whether the value given in the brackets is a solution to the given equation or not.
\n(i) 5n – 7 = 23 (n = 6)
\nAnswer:
\nGiven 5n – 7 = 23
\nWhen n = 6
\nL.H.S = 5n – 7
\n= 5(6) – 7
\n= 30 – 7
\n= 23
\nR.H.S =23
\nHere, L.H.S = R.H.S
\nSo, n = 6 is a solution of the given equation.<\/p>\n

\"AP<\/p>\n

(ii) \\(\\frac{p}{4}\\) – 7 = 5 (p = 8)
\nAnswer:
\nGiven \\(\\frac{p}{4}\\) – 7 = 5; When p = 8
\nLHS = \\(\\frac{p}{4}\\) – 7
\n\"AP
\nRHS = 5
\n– 5 \u2260 5
\nHere, LHS \u2260 RHS
\nSo, p = 8 is not a solution of the given equation.<\/p>\n

(iii) 5 – 2x = 19 -7
\nAnswer:
\nGiven 5 – 2x = 19
\nWhen x = – 7
\nLHS = 5 – 2x
\n= 5 – 2(- 7) = 5 + 14 = 19
\nRHS = 19
\n19 = 19
\nHere, LHS = RHS
\nSo, x = – 7 is a solution of the given equation.<\/p>\n

(iv) 2 + 3(m – 1) = 5 (m = -2)
\nAnswer:
\nGiven 2 + 3(m – 1) = 5
\nWhen m = – 2
\nLHS = 2 + 3(m – 1)
\n= 2 + 3(- 2 – 1)
\n= 2 + 3(- 3) = 2 – 9 = – 7
\nRHS = 5
\n– 7 \u2260 5
\nHere, LHS \u2260 RHS
\nSo, m = – 2 is not a solution of given equation.<\/p>\n

\"AP<\/p>\n

Question 4.
\nSolve the following equations using trial and error method,
\n(i) 3x – 7 = 5
\nAnswer:
\n\"AP
\nFor x = 4, LHS = RHS
\nSo, x = 4 is the solution of given equation.<\/p>\n

(ii) 5 – y = – 1
\nAnswer:
\n\"AP
\nFor y = 6, LHS = RHS.
\nSo, y = 6 is the solution of given equation.<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 3 Simple Equations Ex 3.1 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 3rd Lesson Simple Equations Exercise 3.1 Question 1. Write the equations of the following mathematical statements. (i) A number x decreased by 5 is 14. Answer: Given number = x Number …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21549"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=21549"}],"version-history":[{"count":4,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21549\/revisions"}],"predecessor-version":[{"id":24396,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21549\/revisions\/24396"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=21549"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=21549"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=21549"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}