{"id":21256,"date":"2022-01-10T17:29:55","date_gmt":"2022-01-10T11:59:55","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=21256"},"modified":"2022-01-10T17:29:55","modified_gmt":"2022-01-10T11:59:55","slug":"ap-board-7th-class-maths-solutions-chapter-1-ex-1-4","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-1-ex-1-4\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.4"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 1 Integers Ex 1.4 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Exercise 1.4<\/h2>\n

Question 1.
\nSimplify the following.
\n(i) 6 \u00d7 9 – 6 \u00f7 3
\nAnswer:
\n6 \u00d7 9 – 6 \u00f7 3 (Division)
\n= 6 \u00d7 9 – 2 (Multiplication)
\n= 54 – 2 (Subtraction)
\n= 52<\/p>\n

\"AP<\/p>\n

(ii) 12 \u00f7 4 – 8 + 5
\nAnswer:
\n12 \u00f7 4 – 4 – 8 + 5 (Division)
\n= 3 – 8 + 5
\n= 3 + 5 – 8 (Addition)
\n= 8 – 8 (Subtraction)
\n= 0<\/p>\n

(iii) 80 – 56 \u00f7 8 \u00d7 9
\nAnswer:
\n80 – 56 \u00f7 8 \u00d7 9 (Division)
\n= 80 – 7 \u00d7 9 (Multiplication)
\n= 80 – 63 (Subtraction)
\n= 17<\/p>\n

(iv) 15 \u00f7 5 + 17-30
\nAnswer:
\n15 \u00f7 5 + 17 – 30 (Division)
\n= 3 + 17 – 30 (Addition)
\n= 20 – 30 (Subtraction)
\n= – 10<\/p>\n

(v) 8 + 8 – 8 \u00d7 8 \u00f7 8
\nAnswer:
\n8 + 8 – 8 \u00d7 8 \u00f7 8 (Division)
\n= 8 + 8 – 8 \u00d7 1 (Multiplication)
\n= 8 + 8 – 8 (Addition)
\n= 16 – 8 (Subtraction)
\n= 8<\/p>\n

Question 2.
\nSimplify the following.
\n(i) 8 \u00d7 3 – \\(\\overline{13-7}\\)
\nAnswer:
\n8 \u00d7 3 – \\(\\overline{13-7}\\) (Vinculum)
\n= 8 \u00d7 3 – 6 (Multiplication)
\n= 24 – 6 (Subtraction)
\n= 18<\/p>\n

\"AP<\/p>\n

(ii) {12 – \\(\\overline{14-8}\\) + 7} – 15
\nAnswer:
\n{12 – \\(\\overline{14-8}\\) + 7} – 15 (Vinculum)
\n= {12 – 6 + 7} – 15
\n= {12 + 7 – 6} – 15 (Curly bracket)
\n= {19 – 6} – 15
\n= 13 – 15 (Subtraction)
\n= – 2<\/p>\n

(iii) 16 – (4 + 18 \u00f7 6 – \\(\\overline{7-5}\\)) \u00d7 5
\nAnswer:
\n16 – (4 + 18 \u00f7 6 – \\(\\overline{7-5}\\)) \u00d7 5 (Vinculum)
\n= 16 – (4 + 18 + 6 – 2) \u00d7 5 (Division)
\n= 16 -(4 + 3 – 2) \u00d7 5 (Simple bracket)
\n= 16 – (7 – 2) \u00d7 5
\n= 16 – 5 \u00d7 5 (Multiplication)
\n= 16 – 25 (Subtraction)
\n= – 9<\/p>\n

(iv) {6 of 145 \u00f7 (3 + 2)} \u00f7 2 – 4 of 20
\nAnswer:
\n{6 of 145 \u00f7 (3 + 2)} \u00f7 2 -4 of 20 (Simple Bracket)
\n= {6 of 145 \u00f7 5} \u00f7 2 – 4 of 20 (Of)
\n= {870 \u00f7 5} \u00f7 2 – 80 (Curly bracket, Division)
\n= 174 \u00f7 2 – 80 (Division)
\n= 87 – 80 (Subtraction)
\n= 7<\/p>\n

\"AP<\/p>\n

(v) 25 + [14 – 18 + {12 of 5 – (- 4 + 14)}]
\nAnswer:
\nGiven
\n25 + [14 – 18 + {12 of 5 – (- 4 + 14)}]
\nApplying BODMAS Rule
\n= 25 + [14 – 18 + {12 of 5 – (10)}]
\n[Removing inner most in bracket]
\n= 25 + [14 – 18 + {12 \u00d7 5 – 10}] [Replacing of]
\n= 25 + [14- 18 + {60 – 10}]
\n= 25 + [- 4 + 50]
\n= 25 – 4 + 50
\n= 75 – 4 = 71<\/p>\n

Question 3.
\nIdentify the true statements.
\n(i) 48 \u00f7 6 – 4 = 24
\nAnswer:
\n48 \u00f7 6 – 4 = 24 (Division)
\n8 – 4 = 24 (Subtraction)
\n4 \u2260 24
\nIt is a false statement.<\/p>\n

(ii) – 18 + 12 + 3 = – 14
\nAnswer:
\n– 18 + 12 \u00f7 3 = – 14 (Division)
\n– 18 + 4 = – 14 (Subtraction)
\n– 14 = – 14
\nIt is a true statement.<\/p>\n

(iii) – 11 + 3 \u00d7 7 = – 56
\nAnswer:
\n– 11 + 3 \u00d7 7 = – 56 (Multiplication)
\n– 11 + 21 = – 56 (Subtraction)
\n10 \u2260 – 56
\nIt is a false statement.<\/p>\n

\"AP<\/p>\n

(iv) 2020 \u00f7 20 – 100 = 1
\nAnswer:
\n2020 \u00f7 20 – 100 = 1 (Division)
\n101 – 100 = 1 (Subtraction)
\n1 = 1
\nIt is a true statement.<\/p>\n

Question 4.
\nFill the blanks with +, -, \u00d7, \u00f7 to make the statement as true.
\n(i) 9 __ 3 __ 6 = – 3
\nAnswer:
\n9 \u00f7 3 – 6 = – 3 (Division)
\n3 – 6 = – 3 (Subtraction)
\n– 3 = – 3<\/p>\n

(ii) – 6 __ 12 __ 6 = – 4
\nAnswer:
\n– 6 + 12 \u00f7 6 = – 4 (Division)
\n– 6 + 2 = – 4 (Subtraction)
\n– 4 = – 4<\/p>\n

\"AP<\/p>\n

(iii) – 15 __ 3 __ 6 = – 30
\nAnswer:
\n– 15 \u00f7 3 \u00d7 6 = – 30 (Division)
\n– 5 \u00d7 6 = – 30 (Multiplication)
\n– 30 = – 30<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 1 Integers Ex 1.4 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Exercise 1.4 Question 1. Simplify the following. (i) 6 \u00d7 9 – 6 \u00f7 3 Answer: 6 \u00d7 9 – 6 \u00f7 3 (Division) = 6 \u00d7 9 – …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21256"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=21256"}],"version-history":[{"count":2,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21256\/revisions"}],"predecessor-version":[{"id":21282,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21256\/revisions\/21282"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=21256"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=21256"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=21256"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}