{"id":21217,"date":"2022-01-10T17:38:04","date_gmt":"2022-01-10T12:08:04","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=21217"},"modified":"2022-01-10T17:38:04","modified_gmt":"2022-01-10T12:08:04","slug":"ap-board-7th-class-maths-solutions-chapter-2-ex-2-2","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-2-ex-2-2\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.2"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.2 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Exercise 2.2<\/h2>\n

Question 1.
\nFind the product of the following.
\n(i) 23.4 \u00d7 6
\nAnswer:
\n= \\(\\frac{234}{10} \\times \\frac{6}{1}\\)
\n= \\(\\frac{1404}{10}\\)
\n\u2234 23.4 \u00d7 6 = 140.4<\/p>\n

(ii) 681.25 \u00d7 9
\nAnswer:
\n681.25 \u00d7 9
\n= \\(\\frac{68125}{100} \\times \\frac{9}{1}\\)
\n= \\(\\frac{68125 \\times 9}{100}\\)
\n= \\(\\frac{613125}{100}\\)
\n\u2234 681.25 \u00d7 9
\n= 6131.25<\/p>\n

(iii) 53.29 \u00d7 14
\nAnswer:
\n53.29 \u00d7 14
\n= \\(\\frac{5329}{100} \\times \\frac{14}{1}\\)
\n= \\(\\frac{74606}{100}\\)
\n\u2234 53.29 \u00d7 14
\n= 746.06<\/p>\n

(iv) 8 \u00d7 2.52
\nAnswer:
\n8 \u00d7 2.52
\n= 8 \u00d7 \\(\\frac{252}{100}\\)
\n= \\(\\frac{8 \\times 252}{100}\\)
\n= \\(\\frac{2016}{100}\\)
\n\u2234 8 \u00d7 2.52 = 20.16<\/p>\n

(v) 25 \u00d7 2.013
\nAnswer:
\n25 \u00d7 2.013
\n= 25 \u00d7 \\(\\frac{2013}{1000}\\)
\n= \\(\\frac{25 \\times 2013}{1000}\\)
\n= \\(\\frac{50325}{1000}\\)
\n\u2234 25 \u00d7 2.013 = 50.325<\/p>\n

\"AP<\/p>\n

Question 2.
\nFill the blanks in the table.
\nAnswer:<\/p>\n\n\n\n\n\n\n\n\n\n\n
Multiplications<\/td>\nProduct<\/td>\n<\/tr>\n
36.21 \u00d7 10<\/td>\n362.1<\/td>\n<\/tr>\n
23.104 \u00d7 100<\/td>\n2310.4<\/u><\/td>\n<\/tr>\n
6.24 \u00d7 1000<\/u><\/td>\n6240.0<\/td>\n<\/tr>\n
0.02105<\/u> \u00d7 1000<\/td>\n21.05<\/td>\n<\/tr>\n
9.234 \u00d7 100<\/td>\n923.4<\/u><\/td>\n<\/tr>\n
1.3004 \u00d7 1000<\/u><\/td>\n1300.4<\/td>\n<\/tr>\n
5.9001<\/u> \u00d7 10<\/td>\n59.001<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Question 3.
\nFind the product.
\n(i) 5.1 \u00d7 8.1
\nAnswer:
\n= \\(\\frac{51}{10} \\times \\frac{81}{10}\\)
\n= \\(\\frac{51 \\times 81}{10 \\times 10}\\)
\n= \\(\\frac{4131}{100}\\)
\n\u2234 5.1 \u00d7 8.1 = 41.31<\/p>\n

(ii) 63.205 \u00d7 0.27
\nAnswer:
\n63.205 \u00d7 0.27
\n= \\(\\frac{63205}{1000} \\times \\frac{27}{100}\\)
\n= \\(\\frac{63205 \\times 27}{1000 \\times 100}\\)
\n= \\(\\frac{1706535}{100000}\\)
\n\u2234 63.205 \u00d7 0.27 = 17.06535<\/p>\n

(iii) 1.321 \u00d7 0.9
\nAnswer:
\n1.321 \u00d7 0.9
\n= \\(\\frac{1321}{1000} \\times \\frac{9}{10}\\)
\n= \\(\\frac{1321 \\times 9}{1000 \\times 10}\\)
\n= \\(\\frac{11889}{10000}\\)
\n\u2234 1.321 \u00d7 0.9 = 1.1889<\/p>\n

(iv) 6.51 \u00d7 0.99
\nAnswer:
\n6.51 \u00d7 0.99
\n= \\(\\frac{651}{100} \\times \\frac{99}{100}\\)
\n= \\(\\frac{651 \\times 99}{100 \\times 100}\\)
\n= \\(\\frac{64449}{10000}\\)
\n\u2234 6.51 \u00d7 0.99 = 6.4449<\/p>\n

(v) 837.6 \u00d7 0.006
\nAnswer:
\n837.6 \u00d7 0.006
\n= \\(\\frac{8376}{10} \\times \\frac{6}{1000}\\)
\n= \\(\\frac{8376 \\times 6}{10 \\times 1000}\\)
\n= \\(\\frac{50256}{10000}\\)
\n\u2234 837.6 \u00d7 0.006 = 5.0256<\/p>\n

Question 4.
\nRithesh reads a book for 2.5 hours everyday. If he reads the entire book in a week, then how many hours all together are required for him to read the book ?
\n\"AP
\nAnswer:
\nGiven, time taken to read a book per day = 2.5 hours.<\/p>\n

Time taken to read entire book in a week (one week = 7 days)
\n= 2.5 \u00d7 7 days
\n= \\(\\frac{25}{10}\\) \u00d7 7
\n= \\(\\frac{175}{10}\\)
\n\u2234 Time taken to read entire book = 17.5 hours.<\/p>\n

\"AP<\/p>\n

Question 5.
\nFind the area of the rectangle whose length and breadth are 5.3 cm, 2.7 cm respectively.
\nAnswer:
\nGiven length of the rectangle l = 5.3 cm
\nBreadth of the rectangle b = 2.7 cm
\nArea of the rectangle = l \u00d7 b
\n= 5.3 \u00d7 2.7
\n= \\(\\frac{53}{10} \\times \\frac{27}{10}\\)
\n= \\(\\frac{53 \\times 27}{10 \\times 10}\\)
\n\u2234 Area of the rectangle = \\(\\frac{1431}{100}\\)
\n= 14.31 sq.cm<\/p>\n

Question 6.
\nIf the cost of each cement bag is \u20b9 326.50, then find the cost of 24 bags of cement.
\nAnswer:
\nGiven, cost of each cement bag
\n= \u20b9 326.50<\/p>\n

Cost of 24 cement bags
\n= 326.50 \u00d7 24
\n= \\(\\frac{32650}{100}\\) \u00d7 24
\n= \\(\\frac{32650 \\times 24}{100}\\)
\n= \\(\\frac{783600}{100}\\)<\/p>\n

\u2234 Cost of 24 cement bags = \u20b9 7,836.<\/p>\n

Question 7.
\nDharmika purchased chudidhar material of 1.40 m at the rate of 7152.5 pet irtetre. Find the amount to be paid.
\nAnswer:
\nGiven cost of one meter chudidhar material = 7152.50
\nCost of 1.40 meter chudidhar material = 152.50 \u00d7 1.40
\n= \\(\\frac{15250}{100} \\times \\frac{140}{100}\\)
\n= \\(\\frac{15250 \\times 140}{100 \\times 100}\\)
\n= \\(\\frac{2135000}{10000}\\)
\n\u2234 Cost of 1.40 meter chudidhar material = \u20b9 213.50<\/p>\n

Question 8.
\nIf a picture chart costs 74.25. Amrutha wants to buy 16 charts to make an album. How much money does she has to pay ?
\nAnswer:
\nGiven, cost of one picture chart = \u20b9 4.25
\nCost of 16 charts = 4.25 \u00d7 16
\n= \\(\\frac{425}{100}\\) \u00d7 16
\n= \\(\\frac{425 \\times 16}{100}\\)
\n\u2234 Cost of 16 charts to make album = \\(\\frac{6800}{100}\\) = \u20b9 68<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.2 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Exercise 2.2 Question 1. Find the product of the following. (i) 23.4 \u00d7 6 Answer: = = \u2234 23.4 \u00d7 6 …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21217"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=21217"}],"version-history":[{"count":7,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21217\/revisions"}],"predecessor-version":[{"id":21246,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21217\/revisions\/21246"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=21217"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=21217"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=21217"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}