{"id":21192,"date":"2022-01-10T17:24:48","date_gmt":"2022-01-10T11:54:48","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=21192"},"modified":"2022-01-10T17:28:55","modified_gmt":"2022-01-10T11:58:55","slug":"ap-board-7th-class-maths-solutions-chapter-1-ex-1-1","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-1-ex-1-1\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 1 Integers Ex 1.1"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 1 Integers Ex 1.1 Textbook Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Exercise 1.1<\/h2>\n

Question 1.
\nMultiply the following.
\n(i) 5 \u00d7 7
\nAnswer:
\n5 \u00d7 7 = 35<\/p>\n

\"AP<\/p>\n

(ii) (-9) \u00d7 (6) .
\nAnswer:
\n(-9) \u00d7 (6)
\n= -(9 \u00d7 6) = – 54<\/p>\n

(iii) (9) \u00d7 (-4)
\nAnswer:
\n9 \u00d7 – 4
\n= – (9 \u00d7 4) = – 36<\/p>\n

(iv) (8) \u00d7 (-7)
\nAnswer:
\n8 \u00d7 (-7) = – (8 \u00d7 7) = – 56<\/p>\n

(v) (-124) \u00d7 (-1)
\nAnswer:
\n(-124) \u00d7 (-1) = +(124 \u00d7 1) = + 124<\/p>\n

(vi) (-12) \u00d7 (-7)
\nAnswer:
\n(-12) \u00d7 (-7) = + (12 \u00d7 7) = + 84<\/p>\n

(vii) (-63) \u00d7 (7)
\nAnswer:
\n(-63) \u00d7 (7) = -(63 \u00d7 7) = – 441<\/p>\n

(viii) (7) \u00d7 (-15)
\nAnswer:
\n7 \u00d7 (-15) = – (7 \u00d7 15) = – 105<\/p>\n

\"AP<\/p>\n

Question 2.
\nWhich is greater?
\n(i) 2 \u00d7 (-5) or 3 \u00d7 (-4)
\nAnswer:
\n2 \u00d7 (-5) or 3 \u00d7 (-4)
\n– (2 \u00d7 5) or – (3 \u00d7 4)
\n– 10 or – 12
\n– 10 greater than – 12
\n\u2234(-10) > (-12)<\/p>\n

(ii) (-6) \u00d7 (-7) or (-8) \u00d7 5
\nAnswer:
\n(-6) \u00d7 (-7) or (-8) \u00d7 5
\n6 \u00d7 7 or -(8 \u00d7 5)
\n42 or – 40
\n42 greater than – 40
\n\u2234 42 > (-40)<\/p>\n

(iii) (- 6) \u00d7 10 or (- 3) \u00d7 (- 21)
\nAnswer:
\n(-6) \u00d7 10 or (- 3) \u00d7 (-21)
\n– (6 \u00d7 10) or 3 \u00d7 21
\n– 60 or 63
\n(- 60) less than 63
\n(or)
\n63 greater than (-60)
\n\u2234 63 > (- 60)<\/p>\n

(iv) 9 \u00d7 (-11) or 6 \u00d7 (-16)
\nAnswer:
\n9 \u00d7 (-11) or 6 \u00d7 (-16)
\n-(9 \u00d7 11) or – (6 \u00d7 16)
\n(-99) or (- 96)
\n(- 99) less than (- 96)
\n(- 99) < (- 96)
\n(or)
\n(- 96) greater than (- 99)
\n\u2234 (-96) > (-99)<\/p>\n

\"AP<\/p>\n

(v) (-8) \u00d7 (-5) or (-9) \u00d7 (-4)
\nAnswer:
\n(-8) \u00d7 (-5) or (-9) \u00d7 (-4) + (8 \u00d7 5) or + (9 \u00d7 4)
\n40 or 36
\n40 greater than 36
\n\u2234 40 > 36<\/p>\n

Question 3.
\nWrite the pair of integers whose product will give
\n(i) A negative integer
\nAnswer:
\n\"AP<\/p>\n

(ii) A positive integer
\nAnswer:
\n\"AP<\/p>\n

(iii) Zero
\nAnswer:
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 4.
\nA frog is slipping into a well from upper surface at a rate of 3 meters per minute, after 5 minutes what is the position of the frog in the well?
\n\"AP
\nAnswer:
\nNo. of meters slipped by frog per minute = 3m = – 3 m
\nNo. of meters slipped by frog per 5 minutes = (-3) \u00d7 5
\n= – (3 \u00d7 5)
\n= – 15 m
\nThat is the frog is 15 m down from the upper surface.<\/p>\n

Question 5.
\nDuring the summer, the level of water in a pond decreases by 5 inches every week due to evaporation. What is the change in the level of the water over a period of 6 weeks ?
\n\"AP
\nAnswer:
\nDecrease in water level per every week = 5 inches = (- 5)
\nDecrease in water level per 6 weeks = (-5) \u00d7 6 .
\n= – (5 \u00d7 6)
\n= – 30 inches
\nChange in the level of the water in the pond per 6 weeks is 30 inches decreased.<\/p>\n

\"AP<\/p>\n

Question 6.
\nA shop keeper earns a profit of \u20b9 5 on one note book and loss of \u20b9 3 on one pen by selling in the month of July. He sells 1500 books and 1500 pens. Find out what is his profit or loss.
\nAnswer:
\nProfit on each notebook = \u20b95
\nProfit on 1500 notebooks = 1500 \u00d7 5
\nTotal profit on 1500 note books = \u20b9 75 007\/-
\nLoss on each pen = \u20b93
\nWhich we denoted by – 3.
\nLoss on 1500 pens = 1500 \u00d7 -3
\n= – \u20b9 4500
\nprofit > loss
\nSo, he will get profit.
\nTotal profit = 7500 – 4500
\n= \u20b9 3000\/-<\/p>\n

Question 7.
\nA cement company earns a profit of \u20b9 8 per bag of white cement and a loss of per bag of grey cement by selling.
\nThe company sells 2,000 bags of white cement and 3,000 bags of grey cement in a month. Find out what is its profit or loss.
\nAnswer:
\nProfit on each white cement bag = \u20b9 8
\nProfit on each white cement bag
\n= 2000 \u00d7 8
\n= \u20b9 16000
\nLoss on each grey cement bag = \u20b9 6
\nWhich we denoted by – 6.
\nLoss on 3000 grey cement bags = 3000 \u00d7 – 6
\n= – \u20b9 18000
\nLoss is more than profit.
\nSo, he will get loss.
\n\u2234 Total loss = 16000 + (-18000)
\n= + 16000 – 18000
\n= – 2000\/-<\/p>\n

\"AP<\/p>\n

Question 8.
\nFill in the blanks with suitable integer to make the statement true.
\n(i) (-4) \u00d7 _________ = – 20
\nAnswer:
\n(- 4) \u00d7 5 = – 20
\n(- 4) \u00d7 5 = – 20
\n– (4 \u00d7 5) = – 20
\n– 20 = – 20<\/p>\n

(ii) __________ \u00d7 5 = – 35
\nAnswer:
\n-7 \u00d7 5 = – 35
\n(-7) \u00d7 5 = – 35
\n– (7 \u00d7 5) = – 35
\n– 35 = – 35<\/p>\n

(iii) (-6) \u00d7 __________ = 48
\nAnswer:
\n(-6) \u00d7 (-8) = 48
\n(-6) \u00d7 (-8) = 48
\n6 \u00d7 8 = 48
\n48 = 48<\/p>\n

(iv) __________ \u00d7 (- 9) = 45
\nAnswer:
\n(-5) \u00d7 (-9) = 45
\n(-5) \u00d7 (-9) = 45
\n5 \u00d7 9 = 45
\n45 = 45<\/p>\n

(v) ___________ \u00d7 7 = – 42
\nAnswer:
\n– (6) \u00d7 7) = – 42
\n– (6) \u00d7 7) = – 42
\n– (6 \u00d7 7) = – 42
\n– 42 = – 42<\/p>\n

\"AP<\/p>\n

(vi) 8 \u00d7 = – 8
\nAnswer:
\n8 \u00d7 (-1) = – 8
\n(8) \u00d7 (-1) = – 8 – (8 \u00d7 1) = – 8
\n– 8 = – 8<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 1 Integers Ex 1.1 Textbook Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Exercise 1.1 Question 1. Multiply the following. (i) 5 \u00d7 7 Answer: 5 \u00d7 7 = 35 (ii) (-9) \u00d7 (6) . Answer: (-9) \u00d7 (6) = -(9 \u00d7 …<\/p>\n","protected":false},"author":6,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21192"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/6"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=21192"}],"version-history":[{"count":12,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21192\/revisions"}],"predecessor-version":[{"id":21331,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/21192\/revisions\/21331"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=21192"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=21192"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=21192"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}