{"id":11431,"date":"2021-04-22T18:01:28","date_gmt":"2021-04-22T12:31:28","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=11431"},"modified":"2021-09-15T11:33:05","modified_gmt":"2021-09-15T06:03:05","slug":"ap-board-6th-class-maths-solutions-chapter-10-intext-questions","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-6th-class-maths-solutions-chapter-10-intext-questions\/","title":{"rendered":"AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry InText Questions"},"content":{"rendered":"

AP State Syllabus\u00a0AP Board 6th Class Maths Solutions<\/a> Chapter 10 Practical Geometry InText Questions and Answers.<\/p>\n

AP State Syllabus 6th Class Maths Solutions 10th Lesson Practical Geometry InText Questions<\/h2>\n

\"AP<\/p>\n

Check Your Progress<\/span> (Page No. 139)<\/p>\n

Question 1.
\nMeasure the lengths of \\(\\overline{\\mathrm{AP}}\\) and \\(\\overline{\\mathrm{PB}}\\) in both the constructions. What do you observe?
\nSolution:
\nIn the construction we observe that \\(\\overline{\\mathrm{AP}}=\\overline{\\mathrm{PB}}\\)
\nThat is P can divide AB into two equal parts.
\n\"AP<\/p>\n

Let’s Think<\/span> (Page No. 140)<\/p>\n

Question 1.
\nIn the construction of perpendicular bisector in step 2, what would happen if we take the length of radius to be smaller than half the length of \\(\\overline{\\mathrm{AB}}\\) ?
\nSolution:
\nIf we take the length of radius to be smaller than half the length of \\(\\overline{\\mathrm{AB}}\\)
\nArcs cannot intersect each other. So, we can\u2019t construct the perpendicular bisector to the given line \\(\\overline{\\mathrm{AB}}\\)<\/p>\n

\"AP<\/p>\n

(Page No. 144)<\/p>\n

Question 1.
\nConstruct angles of 180\u00b0, 240\u00b0, 300\u00b0.
\nSolution:
\n\"AP
\ni) \u2220AOB = 180\u00b0
\nSteps of construction:<\/p>\n