{"id":11155,"date":"2021-04-21T11:08:34","date_gmt":"2021-04-21T05:38:34","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=11155"},"modified":"2021-09-15T11:33:32","modified_gmt":"2021-09-15T06:03:32","slug":"ap-board-6th-class-maths-solutions-chapter-6-unit-exercise","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-6th-class-maths-solutions-chapter-6-unit-exercise\/","title":{"rendered":"AP Board 6th Class Maths Solutions Chapter 6 Basic Arithmetic Unit Exercise"},"content":{"rendered":"

AP State Syllabus AP Board 6th Class Maths Solutions<\/a> Chapter 6 Basic Arithmetic Unit Exercise Textbook Questions and Answers.<\/p>\n

AP State Syllabus 6th Class Maths Solutions 6th Lesson Basic Arithmetic Unit Exercise<\/h2>\n

Question 1.
\nDraw a four sided closed figure and divide it into some number of equal parts. Shade the figure with any colour so that the ratio of shaded parts to unshaded parts is 1 : 3.
\nAnswer:
\n\"AP
\nGiven ratio of shaded parts: unshaded parts = 1 : 3
\nTotal parts of a closed figure = 1 + 3 = 4
\nConsider a four sided closed figure square.
\nDivide it into 4 parts and shade one part.
\nNow, from the figure, shaded parts : unshaded parts = 1 : 3<\/p>\n

\"AP<\/p>\n

Question 2.
\nRamu spent \\(\\frac{2}{5}\\)th of his money on a story book. Find the ratio of money spent to the money with him at present.
\nAnswer:
\nGiven money spent on story book = \\(\\frac{2}{5}\\) th of his money.
\nThat means from total 5 parts of money he spent 2 parts of money on story book. Then, out of 5 parts remaining parts of money with him is 3 parts.
\nSo, ratio of money spent to the money with him at present
\n= parts of money spent : parts of money at him = 2 : 3<\/p>\n

Question 3.
\nDivide Rs. 72,000 between Kesav and David in the ratio of 5 : 4.
\nAnswer:
\nAmount to be divided = Rs. 72,000
\nRatio of Kesav and David’s Shares = 5 : 4
\nTotal shares = 5 + 4 = 9
\nKesav’s share = \\(\\frac{5}{9}\\) of 72000
\n\\(\\frac{5}{9}\\) \u00d7 72,000 = 40,000\/-
\nDavid\u2019s share = \\(\\frac{4}{9}\\) of 72,000
\n\\(\\frac{4}{9}\\) \u00d7 72,000 = 32,000\/-<\/p>\n

Question 4.
\nThe income of Kumar for 3 months is Rs. 15,000. If he earns the same amount for a month,
\na) How much will he earn in 5 months?
\nb) In how many months, will he earn Rs. 95,000?
\nAnswer:
\nGiven Kumar’s 3 months income = Rs. 15,000
\nKumar’s one month income = 15,000 \u00f7 3
\n= \\(\\frac{15000}{3}\\) = Rs. 5000
\na) Kumar’s one month income = Rs. 5000
\nKumar\u2019s 5 months income = 5 \u00d7 5000 = Rs. 25,000
\nb) Time taken by Kumar to earn Rs. 5000 = 1 month
\nTime taken by Kumar to earn Rs. 95,000 = 95,000 \u00f7 5000
\n= \\(\\frac{15000}{3}\\) = 19 months = 1 year 7 months.<\/p>\n

\"AP<\/p>\n

Question 5.
\nThe cost of 16 chairs is Rs. 4,800. Find the number of chairs that can be purchased for Rs. 6,600.
\nAnswer:
\nCost of 16 chairs = Rs. 4800
\nNumber of chairs that can be pruchased for Rs. 6600 = x (say)
\n\u2234 16 : 4800 : : x : 6600
\nSo, 16 x 6600 = 4800 x x
\nx = \\(\\frac{16 \\times 6600}{4800}\\) = 22 chairs
\n(OR)
\nGiven cost of 16 chairs = Rs. 4800
\nCost of one chair = 4800 \u00f7 16
\n= \\(\\frac{4800}{3}\\) = Rs. 300
\nNumber of chairs can purchased for Rs. 6600 = 6600 \u00f7 cost of one chair
\n= 6600 \u00f7 300
\n= \\(\\frac{6600}{300}\\) = 22 chairs<\/p>\n

Question 6.
\nWhat percentage of numbers from 1 to 30 has 1 or 9 in the unit\u2019s digit?
\nAnswer:
\nTotal number from 1 to 30 = 30
\nNumbers ending with 1 or 9 are 1, 9,11, 19, 21, 29 = 6 numbers
\nRatio = 6 : 30 = \\(\\frac{6}{30}\\) = \\(\\frac{1}{5}\\)
\nPercentage = \\(\\frac{1}{5}\\) \u00d7 100% = 20%<\/p>\n

\"AP<\/p>\n

Question 7.
\nIn a college, 63% of students are less than 20 years of age. The number of students more than 20 years of age is \u2014 of number of students of 20 years of age which is 42. What is the total number of students in the college?
\nAnswer:
\nLet the total number of students be x.
\nThen, number of students more than 20 years of age = (100 – 63)% of x
\n= 37% of x
\nThen, 37% of x = 42 + \\(\\frac{2}{3}\\) of 48
\n\\(\\frac{37}{100}\\) \u00d7 x = 74
\n\u2234 x = 74 \u00d7 \\(\\frac{100}{37}\\) = 200<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 6 Basic Arithmetic Unit Exercise Textbook Questions and Answers. AP State Syllabus 6th Class Maths Solutions 6th Lesson Basic Arithmetic Unit Exercise Question 1. Draw a four sided closed figure and divide it into some number of equal parts. Shade the figure with any colour …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/11155"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=11155"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/11155\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=11155"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=11155"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=11155"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}