{"id":10944,"date":"2021-04-20T09:47:39","date_gmt":"2021-04-20T04:17:39","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=10944"},"modified":"2021-09-15T11:33:33","modified_gmt":"2021-09-15T06:03:33","slug":"ap-board-6th-class-maths-solutions-chapter-5-ex-5-2","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-6th-class-maths-solutions-chapter-5-ex-5-2\/","title":{"rendered":"AP Board 6th Class Maths Solutions Chapter 5 Fractions and Decimals Ex 5.2"},"content":{"rendered":"

AP State Syllabus AP Board 6th Class Maths Solutions<\/a> Chapter 5 Fractions and Decimals Ex 5.2 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 6th Class Maths Solutions 5th Lesson Fractions and Decimals Ex 5.2<\/h2>\n

Question 1.
\nFind the product of the following.
\ni) 3 \u00d7 \\(\\frac{5}{12}\\)
\nii) \\(\\frac{15}{8}\\) \u00d7 12
\niii) 1\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{12}{21}\\)
\niv) \\(\\frac{4}{5}\\) \u00d7 \\(\\frac{12}{7}\\)
\nAnswer:
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 2.
\nWhich is greater?
\ni) \\(\\frac{1}{2}\\) of \\(\\frac{6}{7}\\) or \\(\\frac{2}{3}\\) of \\(\\frac{3}{7}\\)
\nii) \\(\\frac{2}{7}\\) of \\(\\frac{3}{4}\\) or \\(\\frac{3}{5}\\) of \\(\\frac{5}{8}\\)
\nAnswer:
\ni) \\(\\frac{1}{2}\\) of \\(\\frac{6}{7}\\) or \\(\\frac{2}{3}\\) of \\(\\frac{3}{7}\\)
\n\"AP
\n\\(\\frac{3}{7}\\) or \\(\\frac{2}{7}\\)
\nSo, \\(\\frac{3}{7}\\) > \\(\\frac{2}{7}\\)
\n\u2234 \\(\\frac{1}{2}\\) of \\(\\frac{6}{7}\\) > \\(\\frac{2}{3}\\) of \\(\\frac{3}{7}\\)<\/p>\n

ii) \\(\\frac{2}{7}\\) of \\(\\frac{3}{4}\\) or \\(\\frac{3}{5}\\) of \\(\\frac{5}{8}\\)
\n\"AP
\nConvert them into like fractions
\nLCM of denominators = 2 \u00d7 2 \u00d7 2 \u00d7 7 = 56
\n\\(\\frac{3 \\times 4}{14 \\times 4}\\) or \\(\\frac{3 \\times 7}{8 \\times 7}\\)
\n\\(\\frac{12}{56}\\) or \\(\\frac{21}{56}\\)
\nSo, \\(\\frac{12}{56}\\) < \\(\\frac{21}{56}\\)
\n\u2234 \\(\\frac{2}{7}\\) of \\(\\frac{3}{4}\\) < \\(\\frac{3}{5}\\) of \\(\\frac{5}{8}\\)<\/p>\n

\"AP<\/p>\n

Question 3.
\nFind:
\ni) \\(\\frac{7}{11}\\) of 330
\nii) \\(\\frac{5}{9}\\) of 108
\niii) \\(\\frac{2}{7}\\) of 16
\niv) \\(\\frac{1}{7}\\) of \\(\\frac{3}{10}\\)
\nAnswer:
\ni) \\(\\frac{7}{11}\\) of 330
\n= \\(\\frac{7}{11}\\) \u00d7 330
\n= \\(\\frac{7}{11}\\) \u00d7 11 \u00d7 30
\n= 7 \u00d7 30 = 210<\/p>\n

ii) \\(\\frac{5}{9}\\) of 108
\n= \\(\\frac{5}{9}\\) \u00d7 108
\n= \\(\\frac{5}{9}\\) \u00d7 9 \u00d7 12
\n= 5 \u00d7 12 = 60<\/p>\n

iii) \\(\\frac{2}{7}\\) of 16
\n= \\(\\frac{2}{7}\\) \u00d7 16
\n= \\(\\frac{2\u00d716}{7}\\)
\n= \\(\\frac{32}{7}\\) or 4\\(\\frac{4}{7}\\)<\/p>\n

iv) \\(\\frac{1}{7}\\) of \\(\\frac{3}{10}\\)
\n= \\(\\frac{1}{7}\\) \u00d7 \\(\\frac{3}{10}\\)
\n= \\(\\frac{1 \\times 3}{7 \\times 10}\\)
\n= \\(\\frac{3}{70}\\)<\/p>\n

Question 4.
\nIf the cost of a notebook is Rs. 10\\(\\frac{3}{4}\\). Then, find the cost of 36 books.
\nAnswer:
\nCost of each notebook = Rs. 10\\(\\frac{3}{4}\\) (or) \\(\\frac{43}{4}\\)
\nCost of 36 notebooks = 36 \u00d7 10\\(\\frac{3}{4}\\) = 36 \u00d7 \\(\\frac{43}{4}\\) = \\(\\frac{9 \\times 4 \\times 43}{4}\\) = 9 \u00d7 43
\nCost of 36 notebooks = Rs. 387<\/p>\n

\"AP<\/p>\n

Question 5.
\nA motor bike runs 52\\(\\frac{1}{2}\\) km using 1 litre of petrol. How much distance will it cover for 2\\(\\frac{3}{4}\\) litres of petrol ?
\nAnswer:
\nDistance covered by the motor bike 1 litre petrol = 52\\(\\frac{1}{2}\\) km (or) \\(\\frac{105}{2}\\) km
\nDistance covered by the motor bike for 2\\(\\frac{3}{4}\\) litres of petrol = 2\\(\\frac{3}{4}\\) of 52\\(\\frac{1}{2}\\)
\n= \\(\\frac{11}{4}\\) \u00d7 \\(\\frac{105}{2}\\)
\n= \\(\\frac{11 \\times 105}{4 \\times 2}\\)
\n\u2234 Distance covered by the motor bike for 2\\(\\frac{3}{4}\\) litres of petrol = \\(\\frac{1155}{8}\\) = 144\\(\\frac{3}{8}\\) km.<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 5 Fractions and Decimals Ex 5.2 Textbook Questions and Answers. AP State Syllabus 6th Class Maths Solutions 5th Lesson Fractions and Decimals Ex 5.2 Question 1. Find the product of the following. i) 3 \u00d7 ii) \u00d7 12 iii) 1 \u00d7 iv) \u00d7 Answer: Question …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10944"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=10944"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10944\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=10944"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=10944"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=10944"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}