{"id":10842,"date":"2021-04-19T15:50:30","date_gmt":"2021-04-19T10:20:30","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=10842"},"modified":"2021-09-15T11:33:34","modified_gmt":"2021-09-15T06:03:34","slug":"ap-board-7th-class-maths-solutions-chapter-2-intext-questions","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-2-intext-questions\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 2 Fractions, Decimals and Rational Numbers InText Questions"},"content":{"rendered":"

AP State Syllabus\u00a0AP Board 7th Class Maths Solutions<\/a> Chapter 2 Fractions, Decimals and Rational Numbers InText Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers InText Questions<\/h2>\n

\"AP<\/p>\n

Do This\u00a0<\/span><\/p>\n

Question 1.
\nWrite five examples, each of proper, improper, mixed fractions. ? (Page No. 27)
\nSolution:
\nProper fractions
\n\\(\\frac{1}{5}, \\frac{2}{3}, \\frac{4}{7}, \\frac{3}{8}, \\frac{4}{9}\\)<\/p>\n

Improper fractions
\n\\(\\frac{7}{2}, \\frac{3}{2}, \\frac{9}{4}, \\frac{11}{5}, \\frac{8}{3}\\)<\/p>\n

Mixed fractions
\n\\(1 \\frac{2}{3}, 2 \\frac{3}{5}, 4 \\frac{1}{7}, 8 \\frac{6}{7}\\)<\/p>\n

\"AP<\/p>\n

Question 2.
\nWrite five equivalent fractions for. i) \\(\\frac{3}{5}\\) ii) \\(\\frac{4}{7}\\) (Page No. 28)
\nSolution:
\n\"AP<\/p>\n

Do This<\/span><\/p>\n

Question 1. (Page No. 31)
\ni) 4 x \\(\\frac { 2 }{ 7 }\\)
\nii) 4 x \\(\\frac { 3 }{ 5 }\\)
\niii) 7 x \\(\\frac { 1 }{ 3 }\\)
\nSolution:
\ni) 4 x \\(\\frac{2}{7}=\\frac{4 \\times 2}{7}=\\frac{8}{7}\\)
\nii) 4 x \\(\\frac{3}{5}=\\frac{4 \\times 3}{5}=\\frac{12}{5}\\)
\niii) 7 x \\(\\frac{1}{3}=\\frac{7 \\times 1}{3}=\\frac{7}{3}\\)<\/p>\n

Question 2.
\nFind i) 5 x \\(\\frac { 3 }{ 2 }\\) =
\nii) 4 x \\(\\frac { 7 }{ 5 }\\) =
\niii) 7 x \\(\\frac { 8 }{ 3 }\\) = (Page No. 31)
\nSolution:
\ni) 5 x \\(\\frac{3}{2}=\\frac{5 \\times 3}{2}=\\frac{15}{2}=7 \\frac{1}{2}\\)
\nii) 4 x \\(\\frac{7}{5}=\\frac{4 \\times 7}{5}=\\frac{28}{5}=5 \\frac{3}{5}\\)
\niii) 7 x \\(\\frac{8}{3}=\\frac{7 \\times 8}{3}=\\frac{56}{3}=18 \\frac{2}{3}\\)<\/p>\n

\"AP<\/p>\n

Question 3.
\nFind the following: (Page No. 32)
\ni) 3 x 2 \\(\\frac{2}{7}\\)
\nii) 5 x 2\\(\\frac{1}{3}\\)
\niii) 8 x 4\\(\\frac{1}{7}\\)
\niv) 4 x 1\\(\\frac{2}{9}\\)
\nv) 5 x 1\\(\\frac{1}{3}\\)
\nSolution:
\n\"AP<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nFill in these boxes. (Page No. 35)
\ni) \\(\\frac{1}{5} \\times \\frac{1}{7}=\\frac{1 \\times 1}{5 \\times 7}\\) = ……………
\nii) \\(\\frac{1}{2} \\times \\frac{1}{6}=\\frac{1 \\times 1}{2 \\times 6}=\\) = …………………
\nSolution:
\ni) \\(\\frac{1}{5} \\times \\frac{1}{7}=\\frac{1 \\times 1}{5 \\times 7}=\\frac{1}{35}\\)
\nii) \\(\\frac{1}{2} \\times \\frac{1}{6}=\\frac{1 \\times 1}{2 \\times 6}=\\frac{1}{12}\\)<\/p>\n

Do This<\/span><\/p>\n

Question 1.
\nFind (Page No. 39)
\ni) 2 \u00f7 \\(\\frac{1}{4}\\)
\nii) 7 \u00f7 \\(\\frac{1}{2}\\)
\niii) 3 \u00f7 \\(\\frac{1}{5}\\) (Page No. 39)
\nSolution:
\ni) 2 \u00f7 \\(\\frac{1}{4}=2 \\times \\frac{4}{1}=\\frac{8}{1}\\) = 8
\nii) 7 \u00f7 \\(\\frac{1}{2}=7 \\times \\frac{2}{1}\\) = 14
\niii) 3 \u00f7 \\(\\frac{1}{5}=3 \\times \\frac{5}{1}\\) = 15<\/p>\n

Question 2.
\nFind (Page No. 41)
\ni) 9 \u00f7 \\(\\frac{2}{5}\\)
\nii) 3 \u00f7 \\(\\frac{4}{7}\\)
\niii) 2 \u00f7 \\(\\frac{8}{9}\\)
\nSolution:
\ni) 9 \u00f7 \\(\\frac{2}{5}\\) = \\(9 \\times \\frac{5}{2}=\\frac{45}{2}\\)
\nii) 3 \u00f7 \\(\\frac{4}{7}\\) = \\(3 \\times \\frac{7}{4}=\\frac{21}{4}\\)
\niii) 2 \u00f7 \\(\\frac{8}{9}\\) = \\(2 \\times \\frac{9}{8}=\\frac{9}{4}\\)<\/p>\n

\"AP<\/p>\n

Question 3.
\nFind (Page No. 41)
\ni) 7 \u00f7 5\\(\\frac{1}{3}\\)
\nii) 5 \u00f7 2\\(\\frac{4}{7}\\)
\nSolution:
\ni) 7 \u00f7 5\\(\\frac{1}{3}\\) = \\(7 \\div \\frac{16}{3}=7 \\times \\frac{3}{16}=\\frac{21}{16}\\)
\nii) 5 \u00f7 2\\(\\frac{4}{7}\\) = \\(5 \\div \\frac{18}{7}=5 \\times \\frac{7}{18}=\\frac{35}{18}\\)<\/p>\n

Question 4.
\nFind (Page No. 42)
\ni) \\(\\frac{3}{5} \\div \\frac{1}{2}\\)
\nii) \\(\\frac{1}{2} \\div \\frac{3}{5}\\)
\niii) \\(2 \\frac{1}{2} \\div \\frac{3}{5}\\)
\niv) \\(5 \\frac{1}{6} \\div \\frac{9}{2}\\)
\nSolution:
\n\"AP<\/p>\n

Do This<\/span><\/p>\n

Question
\nFind (Page No. 45)
\ni) 0.25 + 5.30
\nii) 29.75 – 25.97
\nSolution:
\ni) 0.25 + 5.30
\n\"AP<\/p>\n

ii) 29.75 – 25.97
\n\"AP<\/p>\n

\"AP<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nFind (Page No. 48)
\ni) 1.7 x 3
\nii)2.0 x 1.5
\niii) 2.3 x 4.35
\nSolution:
\ni)1.7 x 3 = 5.1
\nii) 2.0 x 1.5 = 3.00
\niii) 2.3 x 4.35 = 10.005<\/p>\n

Question 2.
\nArrange the products obtained in (I) In descending order.
\nSolution:
\nArranging above answers in descending order 10.005 > 5.1 > 3.00<\/p>\n

Question 3.
\nFind (Page No. 50)
\ni) 35.7 \u00f7 3
\nii) 25.5 \u00f7 3
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nFind the greatest and the smallest numbers among the following groups. (Page No. 52)
\ni) 2, -2, -3, 4, 0, -5
\nii) -3, -7, -8,0,-5,-2
\nSolution:
\ni) 2, -2, -3, 4, 0, -5 : greatest number = 4; smallest number = -5
\nii) -3, -7, -8, 0, -5, -2: greatest number = 0; smallest number = -8<\/p>\n

\"AP<\/p>\n

Question 2.
\nWrite the following numbers In ascending order. (Page No. 52)
\ni) -5,-75,3,-2,4, \\(\\frac{3}{2}\\)
\nii) \\(\\frac{2}{3}, \\frac{3}{2}\\), 0, -1, -2, 5
\nSolution:
\ni) -5, -75, 3, -2, 4, \\(\\frac{3}{2}\\)
\nAscending order = -75 <-5 <-2 < \\(\\frac{3}{2}\\) <3 < 4 or -75, -5, -2, \\(\\frac{3}{2}\\), 3, 4<\/p>\n

ii) \\(\\frac{2}{3}\\),\\(\\frac{3}{2}\\), 0, -1, -2, 5
\nAscending order = -2, -1, 0, \\(\\frac{2}{3}\\), \\(\\frac{3}{2}\\), 5<\/p>\n

Question 3.
\nWrite 5 equlvalent rational numbers to (i) \\(\\frac{5}{2}\\) (Page No. 56)
\n(ii) \\(\\frac{-7}{8}\\)
\n(iii) \\(\\frac{-3}{7}\\)
\nSolution:
\n\"AP<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nWhich is bigger \\(\\frac{5}{8}\\) or \\(\\frac{3}{5}\\) ? (PageNo.28)
\nSolution:
\n\\(\\frac{5}{8} \\times \\frac{5}{5}=\\frac{25}{40}\\) and \\(\\frac{3}{5} \\times \\frac{8}{8}=\\frac{24}{40}\\)
\nAs \\(\\frac{24}{40}<\\frac{25}{40}\\) \\(\\frac{5}{8}\\) is bigger than \\(\\frac{3}{5}\\)<\/p>\n

Question 2.
\nDetermine if the following pairs are equal by writing each in their simplest form. (Page No. 28)
\ni) \\(\\frac{3}{8}\\) and \\(\\frac{375}{1000}\\)
\nSolution:
\n\"AP<\/p>\n

ii) \\(\\frac{18}{54}\\) and \\(\\frac{23}{69}\\)
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

iii) \\(\\frac{6}{10}\\) and \\(\\frac{600}{1000}\\)
\nSolution:
\n\"AP<\/p>\n

iv) \\(\\frac{17}{27}\\) and \\(\\frac{25}{45}\\)
\nSolution”
\n\"AP<\/p>\n

Do These <\/span><\/p>\n

Question 1.
\nIdentify the equivalent rational number is each question
\ni) \\(\\frac{-1}{2}, \\frac{-3}{4}, \\frac{-2}{4}, \\frac{-4}{8}\\)
\nSolution:
\n\\(\\frac{-1}{2}=\\frac{-2}{4}=\\frac{-4}{8}\\)<\/p>\n

ii) \\(\\frac{1}{4}, \\frac{3}{4}, \\frac{5}{3}, \\frac{10}{6}, \\frac{2}{4}, \\frac{20}{12}\\)
\nSolution:
\n\\(\\frac{5}{3}=\\frac{20}{12}=\\frac{10}{6}\\)<\/p>\n

\"AP<\/p>\n

Try This <\/span><\/p>\n

Question 1.
\nYou have seen that the product of two natural numbers is one or more than one is bigger than each of the two natural numbers. For example 3 x 4 = 12; 12 > 4 and 12 > 3. What happens to the value of the product when we multiply two proper fractions? (Page No.37)
\nFill the following table and conclude your observations.
\n\"AP
\nSolution:
\n\"AP<\/p>\n

Question 2.
\nWill the reciprocal of a proper fraction be a proper fraction? (Page No. 40)
\nSolution:
\nNo. Reciprocal of a proper fraction is always an improper fraction.<\/p>\n

Question 3.
\nWill the reciprocal of an Improper fraction be an Improper fraction?
\nSolution:
\nNo. The reciprocal of an improper fraction is always a proper fraction.<\/p>\n

\"AP<\/p>\n

Question 4.
\nLook at the following table and fill up the blank spaces. (Page No. 44)
\n\"AP
\nSolution:
\n\"AP<\/p>\n

Question 5.
\nWrIte the following numbers in their expanded form. (Page No.44)
\ni) 30.807
\nii) 968.038
\niii) 8370. 705
\nSolution:
\ni) 30.8O7 = 10 x 3 + 1 x 0 + \\(\\frac{1}{10}\\) x 8 +\\(\\frac{1}{100}\\) x 0 + \\(\\frac{1}{1000}\\) x 7 = 30 + \\(\\frac{8}{10}+\\frac{7}{1000}\\)<\/p>\n

ii) 968.038 = 100 x 9 + 10 x 6 + 1 x 8 + \\(\\frac{1}{10}\\) x 0 + \\(\\frac{1}{100}\\) x 3 + \\(\\frac{1}{1000}\\) x 8 = 900 + 60 + 8 + \\(\\frac{3}{100}+\\frac{8}{1000}\\)<\/p>\n

iii) 8370.705 = 1000 x 8 + 100 x 3 + 10 x 7 + \\(\\frac{1}{10}\\) x 7 + \\(\\frac{1}{1000}\\) x 5 = 8000 + 300 + 70 + \\(\\frac{7}{10}+\\frac{5}{1000}\\)<\/p>\n

\"AP<\/p>\n

Question 6.
\nTake any5 Integers and make all possible rational numbrs with them. (Page No. 54)
\nSolution:
\nConsider 2, 3, 4, 5 and 7
\nRatlonalnumberare \\(\\frac{2}{3}, \\frac{2}{4}, \\frac{2}{5}, \\frac{2}{7}, \\frac{3}{4}, \\frac{3}{5}, \\frac{3}{7}, \\frac{3}{2}, \\frac{4}{2}, \\frac{4}{3}, \\frac{4}{5}, \\frac{4}{7}, \\frac{5}{2}, \\frac{5}{3}, \\frac{5}{4}, \\frac{5}{7}, \\frac{7}{2}, \\frac{7}{3}, \\frac{7}{4}, \\frac{7}{5}\\)<\/p>\n

Question 7.
\nConsider any 5 rational numbers. Find out which itegers constitute them? (Page No.54)
\nSolution:
\nTake \\(\\frac{3}{4}, \\frac{5}{8}, \\frac{6}{11}, \\frac{2}{7}\\) and \\(\\frac{1}{5}\\).
\nThe integers are 1, 2, 3, 4, 5, 6, 7, 8 and 11.<\/p>\n

Do This<\/span><\/p>\n

Question 1.
\nFind (i) 50 paise = \u20b9………….. (ii) 22 g = ………….. kg (iii) 80 cm = ………………m (Page No. 44)
\nSolution:
\n(i) 50 paise =\u20b9\\(\\frac{50}{100}\\) = \u20b9 0.5
\n(ii) 22 g = \\(\\frac{22}{1000}\\) kg = 0.022 kg
\n(iii) 80 cm = \\(\\frac{80}{100}\\) m = 0.8 m<\/p>\n

\"AP<\/p>\n

Try This<\/span><\/p>\n

Question 1.
\nRepresent \\(\\frac{3}{4}\\) and \\(\\frac{1}{4}\\) in different ways using different figures. Justify your representation. Share, and check it with your friends. (Page No.27)
\nSolution:
\n\"AP<\/p>\n

Question 2.
\nRepresents 2 1\/4 pictorially. How many units are needed for this. (Page No. 27)
\nSolution:
\n\"AP
\nWe need 3 units to represent 2\u00bd<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nRepresent pictorially 2 x \\(\\frac{1}{5}=\\frac{2}{5}\\) (Page No. 32)
\nSolution:
\n\"AP<\/p>\n

Do These<\/span><\/p>\n

Question 1.
\nFind \\(\\frac{1}{2} \\times \\frac{1}{5}\\) and \\(\\frac{1}{5} \\times \\frac{1}{2}\\) using diagram check whether \\(\\frac{1}{2} \\times \\frac{1}{5}=\\frac{1}{5} \\times \\frac{1}{2}\\) (Page No. 35)
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

Do These\u00a0<\/span><\/p>\n

Question 1.
\nWrite 5 more fractions between (i) 0 and 1 (ii) 1 and 2. (Page No. 52)
\nSolution:
\ni) Fractions between 0 and 1 are \\(\\frac{1}{7}, \\frac{2}{7}, \\frac{3}{7}, \\frac{4}{7}, \\frac{5}{7}, \\frac{6}{7}\\)
\nii) Fractions between land 2 are \\(\\frac{8}{7}, \\frac{9}{7}, \\frac{10}{7}, \\frac{11}{7}, \\frac{12}{7}, \\frac{13}{7}\\)<\/p>\n

Question 2.
\nWhere does 4\\(\\frac{3}{5}\\) lie on the number line? (Page No. 52)
\nSolution:
\n4\\(\\frac{3}{5}\\) lies between 4 and 5 on the number line.<\/p>\n

Question 3.
\nOn the number line given below represent the following numbei. (Page No.53)
\ni) \\(\\frac{-7}{2}\\)
\nii) \\(\\frac{3}{2}\\)
\niii) \\(\\frac{7}{4}\\)
\niv) \\(\\frac{-7}{4}\\)
\nv) \\(\\frac{-1}{2}\\)
\nvi) \\(\\frac{1}{4}\\)
\n\"AP
\nSolution:
\n\"AP<\/p>\n

Question 4.
\nConsider the following numbers on a number line. (Page No. 53)
\n27, \\(\\frac{-7}{8}, \\frac{11}{943}, \\frac{54}{17}\\), -68, -3, \\(\\frac{-9}{6}, \\frac{7}{2}\\)
\ni) Which of these are to the left of a) 0
\nSolution:
\nLeft to zero are negative numbers
\n\u2234 \\(\\frac{-7}{8}\\), -68, -3, \\(\\frac{-9}{6}\\)<\/p>\n

\"AP<\/p>\n

b) -2
\nLeft to – 2 are less than – 2.
\n\u2234 -3, -68<\/p>\n

c) 4
\nLeft to 4 are less than 4.
\n\"AP<\/p>\n

d) 2
\nLeft to 2 are less than 2.
\n\u2234 \\(\\frac{-7}{8}, \\frac{11}{943}-68,-3, \\frac{-9}{6}\\)<\/p>\n

ii) Which of these would be to the right of
\na) 0
\nRight to zero are positive number.
\n\u2234 \\(27, \\frac{11}{943}, \\frac{54}{17}, \\frac{7}{2}\\)<\/p>\n

b) -5
\nRight to -5 are greater than -5.
\n\\(27, \\frac{-7}{8}, \\frac{11}{943}, \\frac{54}{17}-3, \\frac{-9}{6}, \\frac{7}{2}\\)<\/p>\n

c) 3\\(\\frac{1}{2}\\)
\nRight to 3\\(\\frac{1}{2}\\) are more than 3\\(\\frac{1}{2}\\).
\n\u2234 27<\/p>\n

d) \\(\\frac{-5}{2}\\)
\nRight to \\(\\frac{-5}{2}\\) are more than \\(\\frac{-5}{2}\\)
\n\u2234 \\(-27, \\frac{-7}{8}, \\frac{11}{943}, \\frac{54}{17} \\frac{-9}{6}, \\frac{7}{2}\\)<\/p>\n

\"AP<\/p>\n

Try These<\/span><\/p>\n

Question 1.
\nWrite three more equivalent fractions of \\(\\frac{3}{4}\\) and mark them on the number line. What do you observe? (Page No. 55)
\nSolution:
\nEquivalent fractions of \\(\\frac{3}{4}\\) lie on the same mark.
\n\"AP<\/p>\n

Question 2.
\nDo all equivalent fractions of \\(\\frac{6}{7}\\) represent the same point on the number line.
\n(Page No. 55)
\nSolution:
\nYes.<\/p>\n

Question 3.
\nAre \\(\\frac{-1}{2}\\) and \\(\\frac{-3}{6}\\) represent same point on the number line? (Page No. 55)
\nSolution:
\nYes.<\/p>\n

\"AP<\/p>\n

Question 4.
\nAre \\(\\frac{-2}{3}\\) and \\(\\frac{-4}{6}\\) equivalent? . (Page No. 55)
\nSolution:
\nYes.<\/p>\n

Question 5.
\nMark the following rational numbers on the number line. (In Ex 7,3)
\n(i) \\(\\frac{1}{2}\\)
\n(ii) \\(\\frac{3}{4}\\)
\n(iii) \\(\\frac{3}{2}\\)
\n(iv) \\(\\frac{10}{3}\\)
\nSolution:
\n\"AP<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus\u00a0AP Board 7th Class Maths Solutions Chapter 2 Fractions, Decimals and Rational Numbers InText Questions and Answers. AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers InText Questions Do This\u00a0 Question 1. Write five examples, each of proper, improper, mixed fractions. ? (Page No. 27) Solution: Proper fractions …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10842"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=10842"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10842\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=10842"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=10842"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=10842"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}