{"id":10168,"date":"2021-04-14T11:56:05","date_gmt":"2021-04-14T06:26:05","guid":{"rendered":"https:\/\/apboardsolutions.guru\/?p=10168"},"modified":"2021-09-15T11:34:10","modified_gmt":"2021-09-15T06:04:10","slug":"ap-board-7th-class-maths-solutions-chapter-9-ex-3","status":"publish","type":"post","link":"https:\/\/apboardsolutions.guru\/ap-board-7th-class-maths-solutions-chapter-9-ex-3\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 9 Construction of Triangles Ex 3"},"content":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions<\/a> Chapter 9 Construction of Triangles Ex 3 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 9th Lesson Construction of Triangles Exercise 3<\/h2>\n

\"AP<\/p>\n

Question 1.
\nConstruct \u0394 NET with measurement NE = 6.4 cm, \u2220N = 50\u00b0 and \u2220E = 100\u00b0.
\nSolution:
\nNE = 6.4 cm, \u2220N = 50\u00b0 and \u2220E = 100\u00b0
\n\"AP<\/p>\n

Step -1: Draw a rough sketch of a triangle and label it with the given measurements.
\nStep -2: Draw a Line segment NE of length 6.4 cm.
\nStep -3: Draw a ray \\(\\overrightarrow{\\mathrm{NX}}\\) maktng an angle 50\u00b0 at N.
\nStep -4: Draw a ray \\(\\overrightarrow{\\mathrm{EY}}\\) making an angle 100\u00b0 at E. Extend the ray \\(\\overrightarrow{\\mathrm{NX}}\\) if necessary to intersect ray \\(\\overrightarrow{\\mathrm{EY}}\\)
\nStep – 5: Mark the intersecting point of the two rays as T.
\nWe have the required \u0394NET.<\/p>\n

\"AP<\/p>\n

Question 2.
\nConstruct \u0394PQR such that QR =6 cm, \u2220Q = \u2220R = 60\u00b0. Measure the other two sides of the triangle and name the triangle.
\nSolution:
\n\"AP
\n\"AP
\nQR = 6cm \u2220Q = \u2220R = 60\u00b0.
\nStep -1: Draw a rough sketch of a triangle and label it with the given measurements.
\nStep -2: Draw a line segment QR of length 6 cm.
\nStep -3: Draw a ray \\(\\overrightarrow{\\mathrm{QX}}\\) making an angle 60\u00b0 at Q
\nStep -4: Draw a ray \\(\\overrightarrow{\\mathrm{RY}}\\) making an angle 60\u00b0 at R.
\nStep -5: Mark the intersecting point of the two rays as P. PQ = 6cm and PR = 6 cm
\n\u2234 The triangle is an equilateral triangle.<\/p>\n

\"AP<\/p>\n

Question 3.
\nConstruct \u0394RUN in which RN = 5cm, \u2220R = \u2220N = 45\u00b0. Measure the other angle and other sides. Name the triangle.
\nSolution:
\nRN = 5cm, \u2220R = \u2220N = 45\u00b0.
\n\"AP
\n\"AP
\nStep -1: Draw a rough sketch of a triangle and label it with the given measurements.
\nStep -2: Draw a line segment RN of length 5cm.
\nStep -3: Draw a ray \\(\\overrightarrow{\\mathrm{RX}}\\) making an angle 45\u00b0 at R.
\nStep -4: Draw a ray \\(\\overrightarrow{\\mathrm{NY}}\\) making an angle 45\u00b0 at N.
\nStep -5: Mark the intersecting point of the two rays as U. \u0394RUN is the required triangle
\n\u2220U = 90\u00b0, RU = UN = 3.5 cm.
\n\u2234 The triangle is an isosceles right angled triangle.<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions Chapter 9 Construction of Triangles Ex 3 Textbook Questions and Answers. AP State Syllabus 7th Class Maths Solutions 9th Lesson Construction of Triangles Exercise 3 Question 1. Construct \u0394 NET with measurement NE = 6.4 cm, \u2220N = 50\u00b0 and \u2220E = 100\u00b0. Solution: NE = …<\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10168"}],"collection":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/comments?post=10168"}],"version-history":[{"count":0,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/posts\/10168\/revisions"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/media?parent=10168"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/categories?post=10168"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.guru\/wp-json\/wp\/v2\/tags?post=10168"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}